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Physical & Chemical properties

Vapour pressure

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Link to relevant study record(s)

Reference
Endpoint:
vapour pressure
Type of information:
experimental study
Adequacy of study:
key study
Study period:
Experimental Starting Date: 25 April 2014 Experimental Completion Date: 29 April 2014
Reliability:
1 (reliable without restriction)
Rationale for reliability incl. deficiencies:
other: see 'Remark'
Remarks:
Study conducted in compliance with agreed protocols, with no or minor deviations from standard test guidelines and/or minor methodological deficiencies, which do not affect the quality of the relevant results. The study report was conclusive, done to a valid guideline and the study was conducted under GLP conditions.
Qualifier:
according to guideline
Guideline:
EU Method A.4 (Vapour Pressure)
Deviations:
no
Qualifier:
according to guideline
Guideline:
OECD Guideline 104 (Vapour Pressure Curve)
Deviations:
no
GLP compliance:
yes
Type of method:
effusion method: vapour pressure balance
Temp.:
25 °C
Vapour pressure:
0 Pa
Transition / decomposition:
no

Results

Please see the graphs Runs 6-10 - Graph of Log10 Vapour Pressure vs Reciprocal Temperature in Attachment 2 of this Summary.

Recorded temperatures, mass differences and the resulting calculated values of vapour pressure are shown in the following tables:

 

Run 6

 

Table 3.1– Vapor Pressure Data

 

Temperature (ºC)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass Difference (kg)

Vapor Pressure (Pa)

Log10Vp

170

443.15

0.002256572

14.06

1.406E-08

0.019518882

-1.709545058

171

444.15

0.002251492

13.60

1.360E-08

0.018880284

-1.723991470

172

445.15

0.002246434

13.31

1.331E-08

0.018477690

-1.733352323

173

446.15

0.002241399

14.96

1.496E-08

0.020768313

-1.682598785

174

447.15

0.002236386

15.61

1.561E-08

0.021670679

-1.664127476

175

448.15

0.002231396

17.76

1.776E-08

0.024655430

-1.608087417

176

449.15

0.002226428

19.19

1.919E-08

0.026640636

-1.574455404

177

450.15

0.002221482

20.21

2.021E-08

0.028056658

-1.551964065

178

451.15

0.002216558

20.31

2.031E-08

0.028195483

-1.549820455

179

452.15

0.002211655

21.79

2.179E-08

0.030250103

-1.519273148

180

453.15

0.002206775

24.39

2.439E-08

0.033859569

-1.470318578

 

A plot of Log10(vapor pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 6 gives the following statistical data using an unweighted least squares treatment.

 

Slope:

-5.32 x 103

Standard error in slope:

430

Intercept:

10.3

Standard error in intercept:

0.959

 

The results obtained indicate the following vapor pressure relationship:

 

Log10(Vp (Pa)) = -5.32 x 103/temp(K) + 10.3

 

The above yields a vapor pressure (Pa) at 298.15 K with a common logarithm of -7.59

Run 7

 

Table 3.2 – Vapor Pressure Data

 

Temperature (ºC)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass Difference (kg)

Vapor Pressure (Pa)

Log10Vp

170

443.15

0.002256572

13.70

1.370E-08

0.019019110

-1.720809812

171

444.15

0.002251492

12.66

1.266E-08

0.017575323

-1.755096673

172

445.15

0.002246434

13.52

1.352E-08

0.018769224

-1.726553687

173

446.15

0.002241399

14.12

1.412E-08

0.019602178

-1.707695682

174

447.15

0.002236386

15.71

1.571E-08

0.021809505

-1.661354194

175

448.15

0.002231396

15.83

1.583E-08

0.021976096

-1.658049464

176

449.15

0.002226428

16.64

1.664E-08

0.023100583

-1.636377057

177

450.15

0.002221482

18.30

1.830E-08

0.025405088

-1.595079289

178

451.15

0.002216558

19.85

1.985E-08

0.027556886

-1.559769868

179

452.15

0.002211655

22.72

2.272E-08

0.031541181

-1.501122052

180

453.15

0.002206775

23.89

2.389E-08

0.033165441

-1.479314229

 

A plot of Log10(vapor pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 7 gives the following statistical data using an unweighted least squares treatment.

 

Slope:

-5.42 x 103

Standard error in slope:

490

Intercept:

10.5

Standard error in intercept:

1.09

 

The results obtained indicate the following vapor pressure relationship:

 

Log10(Vp (Pa)) = -5.42 x 103./temp(K) + 10.5

 

The above yields a vapor pressure (Pa) at 298.15 K with a common logarithm of -7.72.

Run 8

 

Table 3.3 – Vapor Pressure Data

 

Temperature (ºC)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass Difference (kg)

Vapor Pressure (Pa)

Log10Vp

170

443.15

0.002256572

12.11

1.211E-08

0.016811783

-1.774386236

171

444.15

0.002251492

11.92

1.192E-08

0.016548014

-1.781254123

172

445.15

0.002246434

12.67

1.267E-08

0.017589206

-1.754753764

173

446.15

0.002241399

13.44

1.344E-08

0.018658163

-1.729131110

174

447.15

0.002236386

13.35

1.335E-08

0.018533220

-1.732049113

175

448.15

0.002231396

15.06

1.506E-08

0.020907138

-1.679705407

176

449.15

0.002226428

16.32

1.632E-08

0.022656341

-1.644810224

177

450.15

0.002221482

16.59

1.659E-08

0.023031170

-1.637683993

178

451.15

0.002216558

17.47

1.747E-08

0.024252836

-1.615237474

179

452.15

0.002211655

21.42

2.142E-08

0.029736448

-1.526710912

180

453.15

0.002206775

20.63

2.063E-08

0.028639725

-1.543031151

 

A plot of Log10(vapor pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 8 gives the following statistical data using an unweighted least squares treatment.

 

Slope:

-5.22 x 103

Standard error in slope:

433

Intercept:

9.98

Standard error in intercept:

0.966

 

The results obtained indicate the following vapor pressure relationship:

 

Log10(Vp (Pa)) = -5.22 x 103/temp(K) + 9.98

 

The above yields a vapor pressure (Pa) at 298.15 K with a common logarithm of -7.54.

Run 9

 

Table 3.4 – Vapor Pressure Data

 

Temperature (ºC)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass Difference (kg)

Vapor Pressure (Pa)

Log10Vp

170

443.15

0.002256572

9.41

9.410E-09

0.013063491

-1.883940755

171

444.15

0.002251492

10.53

1.053E-08

0.014618338

-1.835102008

172

445.15

0.002246434

11.28

1.128E-08

0.015659530

-1.805221279

173

446.15

0.002241399

11.42

1.142E-08

0.015853886

-1.799864275

174

447.15

0.002236386

11.34

1.134E-08

0.015742825

-1.802917324

175

448.15

0.002231396

12.03

1.203E-08

0.016700722

-1.777264751

176

449.15

0.002226428

12.73

1.273E-08

0.017672501

-1.752701975

177

450.15

0.002221482

13.41

1.341E-08

0.018616516

-1.730101601

178

451.15

0.002216558

14.95

1.495E-08

0.020754430

-1.682889186

179

452.15

0.002211655

15.01

1.501E-08

0.020837726

-1.681149686

180

453.15

0.002206775

19.28

1.928E-08

0.026765580

-1.572423349

 

A plot of Log10(vapor pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 9 gives the following statistical data using an unweighted least squares treatment.

 

Slope:

-4.98 x 103

Standard error in slope:

547

Intercept:

9.35

Standard error in intercept:

1.22

 

The results obtained indicate the following vapor pressure relationship:

 

Log10(Vp (Pa)) = -4.98 x 103/temp(K) + 9.35

 

The above yields a vapor pressure (Pa) at 298.15 K with a common logarithm of -7.34.

Run 10

 

Table 3.5 – Vapor Pressure Data

 

Temperature (ºC)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass Difference (kg)

Vapor Pressure (Pa)

Log10Vp

170

443.15

0.002256572

9.60

9.600E-09

0.013327260

-1.875259146

171

444.15

0.002251492

9.70

9.700E-09

0.013466085

-1.870758644

172

445.15

0.002246434

10.59

1.059E-08

0.014701633

-1.832634419

173

446.15

0.002241399

10.43

1.043E-08

0.014479512

-1.839246070

174

447.15

0.002236386

11.36

1.136E-08

0.015770590

-1.802152047

175

448.15

0.002231396

12.37

1.237E-08

0.017172729

-1.765160679

176

449.15

0.002226428

13.20

1.320E-08

0.018324982

-1.736956448

177

450.15

0.002221482

13.91

1.391E-08

0.019310644

-1.714203249

178

451.15

0.002216558

15.12

1.512E-08

0.020990434

-1.677978588

179

452.15

0.002211655

15.23

1.523E-08

0.021143142

-1.674830475

180

453.15

0.002206775

17.82

1.782E-08

0.024738725

-1.606622679

 

A plot of Log10(vapor pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 10 gives the following statistical data using an unweighted least squares treatment.

 

Slope:

-5.30 x 103

Standard error in slope:

303

Intercept:

10.1

Standard error in intercept:

0.676

 

The results obtained indicate the following vapor pressure relationship:

 

Log10(Vp (Pa)) = -5.30 x 103/temp(K) + 10.1

 

The above yields a vapor pressure (Pa) at 298.15 K with a common logarithm of -7.71.

Summary of Results

The values of vapor pressure at 25 °C extrapolated from each graph are summarized in the following table:

 

Table 3.6 – Summary of Vapor Pressure Data

 

Run

Log10[Vp(25ºC)]

6

-7.59

7

-7.72

8

-7.54

9

-7.34

10

-7.71

Mean

-7.58

Vapor Pressure

2.62 x 10-8Pa

 

The test item did not change in appearance under the conditions used in the determination.

Conclusions:
The vapor pressure of the test item has been determined to be 2.6 x 10-8Pa at 25 ºC.
Executive summary:

The determination was carried out using a procedure designed to be compatible with Method A4 Vapour Pressure of Commission Regulation (EC) No 440/2008 of 30 May 2008 and Method 104 of the OECD Guidelines for Testing of Chemicals, 23 March 2006.

 

Instrument:                                               Vapor pressure balance.

Conclusion

The vapor pressure of the test item has been determined to be 2.6 x 10-8Pa at 25 ºC.

Description of key information

The determination was carried out using a procedure designed to be compatible with Method A4 Vapour Pressure of Commission Regulation (EC) No 440/2008 of 30 May 2008 and Method 104 of the OECD Guidelines for Testing of Chemicals, 23 March 2006.Instrument: Vapor pressure balance.

Key value for chemical safety assessment

Vapour pressure:
0 Pa
at the temperature of:
25 °C

Additional information