Registration Dossier

Administrative data

Endpoint:
vapour pressure
Type of information:
experimental study
Adequacy of study:
key study
Study period:
Experimental starting date: 28 June 2016 Experimental completion date: 05 July 2016
Reliability:
1 (reliable without restriction)

Data source

Reference
Reference Type:
study report
Title:
Unnamed
Year:
2016
Report Date:
2016

Materials and methods

Test guidelineopen allclose all
Qualifier:
according to
Guideline:
EU Method A.4 (Vapour Pressure)
Qualifier:
according to
Guideline:
OECD Guideline 104 (Vapour Pressure Curve)
GLP compliance:
yes
Type of method:
effusion method: vapour pressure balance

Test material

Reference
Name:
Unnamed
Type:
Constituent
Type:
Constituent
Test material form:
liquid
Specific details on test material used for the study:
Information as provided by the Sponsor. The Certificate of Analysis provided by the Sponsor is presented as Annex 3 (Please see Attachment Section of this Summary).

Identification: X-19574
Appearance/Physical state: Amber colored viscous liquid
Batch: X-019574-00-00
Purity: UVCB (treat as 100%)
Expiry: 01 June 2017
Storage conditions: Room temperature in the dark

Results and discussion

Vapour pressure
Temp.:
25 °C
Vapour pressure:
0.022 Pa

Any other information on results incl. tables

Results

Please see the Attachment Section of this report for Figures 2 to 5 Graphs of Log10Vapor Pressure vs Reciprocal Temperature Runs 2 to 5.

Recorded temperatures, mass differences and the resulting calculated values of vapor pressure are shown in the following tables:

Run 2

Table 1 – Vapor Pressure Data

Temperature (ºC)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass Difference (kg)

Vapor Pressure (Pa)

Log10Vp

35

308.15

0.003245173

38.86

3.886E-08

0.053947636

-1.268027582

36

309.15

0.003234676

38.00

3.800E-08

0.052753736

-1.277746782

37

310.15

0.003224246

45.90

4.590E-08

0.063720960

-1.195717693

38

311.15

0.003213884

52.07

5.207E-08

0.072286500

-1.140942801

39

312.15

0.003203588

53.29

5.329E-08

0.073980173

-1.130884658

40

313.15

0.003193358

59.07

5.907E-08

0.082004294

-1.086163408

41

314.15

0.003183193

66.44

6.644E-08

0.092235742

-1.035100755

42

315.15

0.003173092

70.86

7.086E-08

0.098371834

-1.007129231

43

316.15

0.003163056

74.27

7.427E-08

0.103105788

-0.986716955

44

317.15

0.003153082

79.94

7.994E-08

0.110977201

-0.954766235

45

318.15

0.003143171

87.55

8.755E-08

0.121541830

-0.915274228

A plot of Log10(vapor pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 2 gives the following statistical data using an unweighted least squares treatment.

Slope:

-3.61 x 103

Standard error in slope:

164

 

Intercept:

10.4

Standard error in intercept:

0.524

The results obtained indicate the following vapor pressure relationship:

Log10(Vp (Pa)) = -3.61 x 103/temp(K) + 10.4

The above yields a vapor pressure (Pa) at 298.15 K with a common logarithm of -1.67.

Run 3

Table 2 – Vapor Pressure Data

Temperature (ºC)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass Difference (kg)

Vapor Pressure (Pa)

Log10Vp

35

308.15

0.003245173

39.76

3.976E-08

0.055197066

-1.258084003

36

309.15

0.003234676

43.36

4.336E-08

0.060194789

-1.220441105

37

310.15

0.003224246

46.58

4.658E-08

0.064664974

-1.189330895

38

311.15

0.003213884

49.14

4.914E-08

0.068218910

-1.166095227

39

312.15

0.003203588

54.18

5.418E-08

0.075215721

-1.123691378

40

313.15

0.003193358

61.41

6.141E-08

0.085252813

-1.069291281

41

314.15

0.003183193

62.91

6.291E-08

0.087335197

-1.058810694

42

315.15

0.003173092

72.47

7.247E-08

0.100606927

-0.997372117

43

316.15

0.003163056

75.94

7.594E-08

0.105424176

-0.977059786

44

317.15

0.003153082

82.54

8.254E-08

0.114586667

-0.940865914

45

318.15

0.003143171

89.70

8.970E-08

0.124526581

-0.904737936

A plot of Log10(vapor pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 3 gives the following statistical data using an unweighted least squares treatment.

Slope:

-3.50 x 103

Standard error in slope:

85.4

 

Intercept:

10.1

Standard error in intercept:

0.273

The results obtained indicate the following vapor pressure relationship:

Log10(Vp (Pa)) = -3.50 x 103/temp(K) + 10.1

The above yields a vapor pressure (Pa) at 298.15 K with a common logarithm of -1.64.

Run 4

Table 3 – Vapor Pressure Data

Temperature (ºC)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass Difference (kg)

Vapor Pressure (Pa)

Log10Vp

35

308.15

0.003245173

37.47

3.747E-08

0.052017960

-1.283846686

36

309.15

0.003234676

49.31

4.931E-08

0.068454913

-1.164595376

37

310.15

0.003224246

44.12

4.412E-08

0.061249863

-1.212894875

38

311.15

0.003213884

50.31

5.031E-08

0.069843169

-1.155876061

39

312.15

0.003203588

55.71

5.571E-08

0.077339753

-1.111597220

40

313.15

0.003193358

57.40

5.740E-08

0.079685906

-1.098618486

41

314.15

0.003183193

68.50

6.850E-08

0.095095550

-1.021839807

42

315.15

0.003173092

69.45

6.945E-08

0.096414393

-1.015858129

43

316.15

0.003163056

77.25

7.725E-08

0.107242791

-0.969631891

44

317.15

0.003153082

81.83

8.183E-08

0.113601005

-0.944617828

45

318.15

0.003143171

90.65

9.065E-08

0.125845424

-0.900162570

A plot of Log10(vapor pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 4 gives the following statistical data using an unweighted least squares treatment.

Slope:

-3.47 x 103

Standard error in slope:

235

 

Intercept:

10.0

Standard error in intercept:

0.752

The results obtained indicate the following vapor pressure relationship:

Log10(Vp (Pa)) = -3.47 x 103/temp(K) + 10.0

The above yields a vapor pressure (Pa) at 298.15 K with a common logarithm of -1.64.

Run 5

Table 4 – Vapor Pressure Data

Temperature (ºC)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass Difference (kg)

Vapor Pressure (Pa)

Log10Vp

35

308.15

0.003245173

37.00

3.700E-08

0.051365479

-1.289328655

36

309.15

0.003234676

41.60

4.160E-08

0.057751458

-1.238437048

37

310.15

0.003224246

47.24

4.724E-08

0.065581223

-1.183220490

38

311.15

0.003213884

51.69

5.169E-08

0.071758963

-1.144123847

39

312.15

0.003203588

54.44

5.444E-08

0.075576667

-1.121612262

40

313.15

0.003193358

58.39

5.839E-08

0.081060279

-1.091191903

41

314.15

0.003183193

60.51

6.051E-08

0.084003383

-1.075703226

42

315.15

0.003173092

68.17

6.817E-08

0.094637425

-1.023937085

43

316.15

0.003163056

75.57

7.557E-08

0.104910521

-0.979180957

44

317.15

0.003153082

89.54

8.954E-08

0.124304460

-0.905513289

45

318.15

0.003143171

87.70

8.770E-08

0.121750069

-0.914530785

A plot of Log10(vapor pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 5 gives the following statistical data using an unweighted least squares treatment.

Slope:

-3.66 x 103

Standard error in slope:

167

 

Intercept:

10.6

Standard error in intercept:

0.534

The results obtained indicate the following vapor pressure relationship:

Log10(Vp (Pa)) = -3.66 x 103/temp(K) + 10.6

The above yields a vapor pressure (Pa) at 298.15 K with a common logarithm of -1.67.

The values of vapor pressure at 25 °C extrapolated from each graph are summarized in the following table:

Table 5            Summary of Vapor Pressure Data

Run

Log10[Vp(25 ºC)]

2

-1.67

3

-1.64

4

-1.64

5

-1.67

Mean

-1.66

Vapor Pressure

2.21 x 10-2Pa

The test item did not change in appearance under the conditions used in the determination.

Applicant's summary and conclusion

Conclusions:
The vapor pressure of the test item has been determined to be 2.2 x 10-2 Pa at 25 ºC.
Executive summary:

The determination was carried out using a procedure designed to be compatible with Method A.4 Vapour Pressure of Commission Regulation (EC) No 440/2008 of 30 May 2008 and Method 104 of the OECD Guidelines for Testing of Chemicals, 23 March 2006.

Conclusion

The vapor pressure of the test item has been determined to be 2.2 x 10-2Pa at 25 ºC.