Fatty acids, C16-18 and C18-unsatd., branched and linear, reaction products with diethanolamine

Vapour pressure

Administrative data

Endpoint:

vapour pressure

Type of information:

experimental study

Adequacy of study:

key study

Study period:

Between 22 May 2012 and 25 May 2012.

Reliability:

1 (reliable without restriction)

Rationale for reliability incl. deficiencies:

other: see 'Remark'

Remarks:

Study conducted in compliance with agreed protocols, with no or minor deviations from standard test guidelines and/or minor methodological deficiencies, which do not affect the quality of the relevant results. The study report was conclusive, done to a valid guideline and the study was conducted under GLP conditions.

Data source

Reference

Reference Type:

study report

Title:

Unnamed

Year:

2012

Report date:

2012

Materials and methods

Test guideline

Qualifier:

according to guideline

Guideline:

EU Method A.4 (Vapour Pressure)

Deviations:

no

GLP compliance:

yes

Type of method:

effusion method: vapour pressure balance

Test material

Test material information

Constituent 1

Reference substance name:

Isostearamide DEA

IUPAC Name:

Isostearamide DEA

Details on test material:

Identification: Isostearamide DEA
Description: amber colored liquid
Batch: OE11124 (6/202593/00)
Purity: not supplied
Expiry / Retest Date: not supplied
Storage Conditions: room temperature in the dark

Results and discussion

Vapour pressure

Temp.:

25 °C

Vapour pressure:

0.001 Pa

Transition / decomposition

Transition / decomposition:

no

Any other information on results incl. tables

Results

A total of ten runs were completed for the main sequence. Equilibrium with regard to vapor pressure was assessed to have been reached over the final four runs. Thus the final four runs have been used to calculate the definitive vapor pressure value for the test item. The results for runs 1 to 6 are shown in Appendix 3 - Attachment 2.

 

Recorded temperatures, mass differences and the resulting calculated values of vapor pressure for the final four runs are shown in the following tables and the graphs are shown in Attachment 3:

Table 3.1 – Vapor Pressure Data

 

Temperature (ºC)	Temperature (K)	Reciprocal Temperature (K^-1)	Mass Difference (µg)	Mass Difference (kg)	Vapor Pressure (Pa)	Log10Vp
104	377.15	0.002651465	177.22	1.772E-07	0.246026764	-0.609017647
105	378.15	0.002644453	178.52	1.785E-07	0.247831497	-0.605843501
106	379.15	0.002637479	177.42	1.774E-07	0.246304415	-0.608527804
107	380.15	0.002630541	193.80	1.938E-07	0.269044051	-0.570176606
108	381.15	0.002623639	203.48	2.035E-07	0.282482371	-0.549008650
109	382.15	0.002616774	217.56	2.176E-07	0.302029019	-0.519951329
110	383.15	0.002609944	231.34	2.313E-07	0.321159189	-0.493279647
111	384.15	0.002603150	234.33	2.343E-07	0.325310075	-0.487702486
112	385.15	0.002596391	253.40	2.534E-07	0.351784121	-0.453723768
113	386.15	0.002589667	275.47	2.755E-07	0.382422935	-0.417456070
114	387.15	0.002582978	294.14	2.941E-07	0.408341678	-0.388976291

 

A plot of log₁₀(vapor pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 7 gives the following statistical data using an unweighted least squares treatment.

 

Slope  -3.37 x 10³
Standard deviation in slope   197

 

Intercept         8.29
Standard deviation in intercept         0.517

 

The results obtained indicate the following vapor pressure relationship:

 

Log₁₀(Vp (Pa)) = -3.37 x 10³/temp(K) + 8.29

 

The above yields a vapor pressure (Pa) at 298.15 K with a common logarithm of -3.00.

Run 8

 

Table 3.2 – Vapor Pressure Data

 

Temperature (ºC)	Temperature (K)	Reciprocal Temperature (K^-1)	Mass Difference (µg)	Mass Difference (kg)	Vapor Pressure (Pa)	Log10Vp
104	377.15	0.002651465	170.23	1.702E-07	0.236322853	-0.626494280
105	378.15	0.002644453	170.73	1.707E-07	0.237016981	-0.625220538
106	379.15	0.002637479	183.11	1.831E-07	0.254203593	-0.594818316
107	380.15	0.002630541	194.89	1.949E-07	0.270557251	-0.567740823
108	381.15	0.002623639	201.18	2.012E-07	0.279289382	-0.553945575
109	382.15	0.002616774	204.98	2.050E-07	0.284564756	-0.545818890
110	383.15	0.002609944	224.55	2.246E-07	0.311732929	-0.506217319
111	384.15	0.002603150	242.72	2.427E-07	0.336957545	-0.472424815
112	385.15	0.002596391	249.31	2.493E-07	0.346106153	-0.460790680
113	386.15	0.002589667	267.18	2.672E-07	0.370914291	-0.430726433
114	387.15	0.002582978	291.44	2.914E-07	0.404593387	-0.392981220

 

A plot of log₁₀(vapor pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 8 gives the following statistical data using an unweighted least squares treatment.

 

Slope  -3.43 x 10³
Standard deviation in slope   158

 

Intercept         8.45
Standard deviation in intercept         0.415

 

The results obtained indicate the following vapor pressure relationship:

 

Log₁₀(Vp (Pa)) = -3.43 x 10³/temp(K) + 8.45

 

The above yields a vapor pressure (Pa) at 298.15 K with a common logarithm of -3.05.

 

Run 9

 

Table 3.3 – Vapor Pressure Data

 

Temperature (ºC)	Temperature (K)	Reciprocal Temperature (K^-1)	Mass Difference (µg)	Mass Difference (kg)	Vapor Pressure (Pa)	Log10Vp
104	377.15	0.002651465	157.45	1.575E-07	0.218580938	-0.660387714
105	378.15	0.002644453	166.64	1.666E-07	0.231339013	-0.635751122
106	379.15	0.002637479	178.22	1.782E-07	0.247415020	-0.606573939
107	380.15	0.002630541	186.71	1.867E-07	0.259201315	-0.586362800
108	381.15	0.002623639	218.16	2.182E-07	0.302861972	-0.518755254
109	382.15	0.002616774	218.56	2.186E-07	0.303417275	-0.517959697
110	383.15	0.002609944	224.15	2.242E-07	0.311177627	-0.506991636
111	384.15	0.002603150	227.94	2.279E-07	0.316439118	-0.499709835
112	385.15	0.002596391	238.93	2.389E-07	0.331696054	-0.479259696
113	386.15	0.002589667	258.89	2.589E-07	0.359405647	-0.444415103
114	387.15	0.002582978	269.38	2.694E-07	0.373968455	-0.427165030

 

A plot of log₁₀(vapor pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 9 gives the following statistical data using an unweighted least squares treatment.

 

Slope  -3.32 x 10³
Standard deviation in slope   224

 

Intercept         8.15
Standard deviation in intercept         0.585

 

The results obtained indicate the following vapor pressure relationship:

 

Log₁₀(Vp (Pa)) = -3.32 x 10³/temp(K) + 8.15

 

The above yields a vapor pressure (Pa) at 298.15 K with a common logarithm of -2.98.

Run 10

 

Table 3.4 – Vapor Pressure Data

 

Temperature (ºC)	Temperature (K)	Reciprocal Temperature (K^-1)	Mass Difference (µg)	Mass Difference (kg)	Vapor Pressure (Pa)	Log10Vp
104	377.15	0.002651465	152.96	1.530E-07	0.212347668	-0.672952504
105	378.15	0.002644453	158.75	1.588E-07	0.220385672	-0.656816645
106	379.15	0.002637479	168.74	1.687E-07	0.234254351	-0.630312334
107	380.15	0.002630541	185.31	1.853E-07	0.257257756	-0.589631523
108	381.15	0.002623639	191.30	1.913E-07	0.265573411	-0.575815409
109	382.15	0.002616774	196.59	1.966E-07	0.272917286	-0.563968956
110	383.15	0.002609944	211.47	2.115E-07	0.293574538	-0.532281613
111	384.15	0.002603150	221.15	2.212E-07	0.307012858	-0.512843435
112	385.15	0.002596391	233.93	2.339E-07	0.324754773	-0.488444458
113	386.15	0.002589667	239.22	2.392E-07	0.332098648	-0.478732893
114	387.15	0.002582978	251.31	2.513E-07	0.348882665	-0.457320609

 

A plot of log₁₀(vapor pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 10 gives the following statistical data using an unweighted least squares treatment.

 

Slope  -3.20 x 10³
Standard deviation in slope   103

 

Intercept         7.83
Standard deviation in intercept         0.269

 

The results obtained indicate the following vapor pressure relationship:

 

Log₁₀(Vp (Pa)) = -3.20 x 10³/temp(K) + 7.83

 

The above yields a vapor pressure (Pa) at 298.15 K with a common logarithm of -2.92.

Summary of Results

 

The values of vapor pressure at 25 °C extrapolated from each graph are summarized in the following table:

 

Table 3.6 – Summary of Vapor Pressure Data

 

Run	Log10 [Vp(25 ºC)]
7	-3.00
8	-3.05
9	-2.98
10	-2.92
Mean	-2.99
Vapor Pressure	1.0 x 10^-3Pa

 

The test item did not change in appearance under the conditions used in the determination.

 

Applicant's summary and conclusion

Conclusions:

Please see the Executive Summary for the conclusion.

Executive summary:

The determination was carried out using a procedure designed to be compatible with Method A4 Vapour Pressure of Commission Regulation (EC) No 440/2008 of 30 May 2008 and Method 104 of the OECD Guidelines for Testing of Chemicals, 23 March 2006.

Summary of Results

 

The values of vapor pressure at 25 °C extrapolated from each graph are summarized in the following table:

 

Table 3.6 – Summary of Vapor Pressure Data

 

Run		Log10 [Vp(25 ºC)]
7		-3.00
8		-3.05
9		-2.98
10		-2.92
Mean		-2.99
Vapor Pressure		1.0 x 10^-3Pa

 

The test item did not change in appearance under the conditions used in the determination.

 

Discussion

A total of ten runs were completed for the main sequence. Equilibrium with regard to vapor pressure was assessed to have been reached over the final four runs. Thus the final four runs have been used to calculate the definitive vapor pressure value for the test item.

 

Conclusion

The vapor pressure of the test item has been determined to be 1.0 x 10^-3Pa at 25 ºC.