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Vapour pressure

Link to relevant study record(s)

Reference

Reference 1

Endpoint:

vapour pressure

Type of information:

experimental study

Adequacy of study:

key study

Study period:

16-07-2019 to 24-10-2019

Reliability:

1 (reliable without restriction)

Rationale for reliability incl. deficiencies:

other: Guideline study performed under GLP. All relevant validity criteria were met.

Qualifier:

according to guideline

Guideline:

EU Method A.4 (Vapour Pressure)

Deviations:

no

Qualifier:

according to guideline

Guideline:

OECD Guideline 104 (Vapour Pressure Curve)

Deviations:

no

Qualifier:

according to guideline

Guideline:

EPA OPPTS 830.7950 (Vapor Pressure)

Deviations:

no

GLP compliance:

yes (incl. QA statement)

Remarks:

inspected: August 2018 ; signature: November 2018

Type of method:

effusion method: vapour pressure balance

Temp.:

25 °C

Vapour pressure:

0.149 Pa

Remarks on result:

other: Mean Vp (n=9): extrapolated from log Vp (Pa) vs. 1/T curve of nine (9) individual runs (the first of ten runs was not included due to not having reached equilibrium)

Test no.:

#1

Temp.:

25 °C

Vapour pressure:

0.149 Pa

Test no.:

#2

Temp.:

25 °C

Vapour pressure:

0.15 Pa

Test no.:

#3

Temp.:

25 °C

Vapour pressure:

0.15 Pa

Test no.:

#4

Temp.:

25 °C

Vapour pressure:

0.152 Pa

Test no.:

#5

Temp.:

25 °C

Vapour pressure:

0.151 Pa

Test no.:

#6

Temp.:

25 °C

Vapour pressure:

0.145 Pa

Test no.:

#7

Temp.:

25 °C

Vapour pressure:

0.147 Pa

Test no.:

#8

Temp.:

25 °C

Vapour pressure:

0.152 Pa

Test no.:

#9

Temp.:

25 °C

Vapour pressure:

0.148 Pa

Transition / decomposition:

no

Remarks on result:

other: The test item did not change in appearance under the conditions used in the determination

Table 1.0 – vapour pressure determination of the test item

Run	Log10Vp(25°C)	Vp(25°C) [Pa]
1	-0.828	0.149
2	-0.823	0.150
3	-0.823	0.150
4	-0.818	0.152
5	-0.822	0.151
6	-0.838	0.145
7	-0.832	0.147
8	-0.818	0.152
9	-0.830	0.148
Mean	-0.826	0.149

 

Note the first of ten runs was excluded from assessment as the system had not reached equilibrium (details provided in the full study report).

 

The slope and intercept of the nine (9) individual runs for theplot  ofLog10Vp(Pa) versus reciprocal of temperature (K) is recorded in the full study report. A total of 10 runs were completed for the main sequence. Run 1 was not utilised as the sample was still equilibrating.With regard toequilibrium, this has been assessed to have been reached over runs 1 to 9 (actual #2 to #10) which were used to calculate the vapour pressure. There was no evidence of decomposition during the course of the test (no change in appearance).

Conclusions:

The vapour pressure of the test item has been determined to be 0.149 Pa at 25 °C.

Executive summary:

The vapour pressure was determined using EU Method A.4 guideline using the vapour pressure balance method under GLP. Measurements being made at several temperatures and linear regression analysis used to calculate the vapour pressure at 25°C. The temperature of the sample was controlled electronically. The mass and temperature readings were recorded automatically into a computer file. The difference in mass readings with the orifice covered and uncovered is proportional to the vapour pressure at the given oven temperature. Temperature and pressure readings were taken between 25 and 35°C with a one-hour dwell time at 25°C between runs. The vapour pressure of the test item was extrapolated from the vapour pressure curve (log10Vpversus 1/T). The mean vapour pressure based on nine runs was 0.149 Pa at 25°C.

Reference 2

Endpoint:

vapour pressure

Type of information:

experimental study

Adequacy of study:

key study

Study period:

09 April 2021 - 13 April 2021

Reliability:

1 (reliable without restriction)

Rationale for reliability incl. deficiencies:

guideline study

Remarks:

Study conducted according to Method A.4 Vapour Pressure of Commission Regulation (EC) No 440/2008 of 30 May 2008 and Method 104 of the OECD Guidelines for Testing of Chemicals, 23 March 2006 and OCSPP 830.7950 of the US EPA Office of Chemical Safety and Pollution Prevention (OCSPP), Series 830: Product Properties Test Guidelines.

Qualifier:

according to guideline

Guideline:

EPA OPPTS 830.7950 (Vapor Pressure)

Qualifier:

according to guideline

Guideline:

OECD Guideline 104 (Vapour Pressure Curve)

Deviations:

no

Qualifier:

according to guideline

Guideline:

EU Method A.4 (Vapour Pressure)

Deviations:

no

GLP compliance:

yes (incl. QA statement)

Remarks:

Signature : August 2021

Type of method:

effusion method: vapour pressure balance

Key result

Temp.:

25 °C

Vapour pressure:

ca. 0.132 Pa

Remarks on result:

other: Mean

Results:

The test item appearance was recorded before and after testing as a clear, pale yellow liquid, thus no change in appearance of the test item occured under the conditions used during the study. 

Recorded temperatures, mass differences and the resulting calculated values of vapor pressure are shown in the following tables: 

Run 1:

Table 1 - Vapor Pressure Data

Temperature (ºC)	Temperature (K)	Reciprocal Temperature (K^-1)	Mass Difference (µg)	Mass Difference (kg)	Vapor Pressure (Pa)	Log10 Vp
28	301.15	0.003321	115.28	1.153e-07	0.16004	-0.79577
29	302.15	0.003310	118.64	1.186e-07	0.16470	-0.78331
30	303.15	0.003299	125.84	1.258e-07	0.17470	-0.75771
31	304.15	0.003288	135.54	1.355e-07	0.18816	-0.72547
32	305.15	0.003277	141.89	1.419e-07	0.19698	-0.70558
33	306.15	0.003266	153.47	1.535e-07	0.21306	-0.67150
34	307.15	0.003256	166.37	1.664e-07	0.23096	-0.63646
35	308.15	0.003245	178.61	1.786e-07	0.24796	-0.60562
36	309.15	0.003235	194.48	1.945e-07	0.26999	-0.56865
37	310.15	0.003224	213.80	2.138e-07	0.29681	-0.52752
38	311.15	0.003214	226.08	2.261e-07	0.31386	-0.50326

A plot of Log₁₀(vapor pressure (Pa)) versus reciprocal temperature (1/T (K)) for Run 1 gives the following statistical data using an unweighted least square treatment.

 

Slope:                                  -2.85 x 10³ 

Standard error in slope:       98.3

Intercept:                              8.65

Standard error in intercept: 0.321

 

The results obtained indicate the following vapour pressure relationship: 

Log₁₀(Vp (Pa)) = -2.85 x 10³ / temp (K) + 8.65

 

The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -0.910.

 

 

Run 2:

Table 2 - Vapor Pressure Data

Temperature (ºC)	Temperature (K)	Reciprocal Temperature (K^-1)	Mass Difference (µg)	Mass Difference (kg)	Vapor Pressure (Pa)	Log10 Vp
28	301.15	0.003321	126.15	1.262e-07	0.17513	-0.75664
29	302.15	0.003310	125.59	1.256e-07	0.17435	-0.75858
30	303.15	0.003299	131.64	1.316e-07	0.18275	-0.73814
31	304.15	0.003288	138.24	1.382e-07	0.19191	-0.71690
32	305.15	0.003277	149.42	1.494e-07	0.20743	-0.68313
33	306.15	0.003266	160.33	1.603e-07	0.22258	-0.65251
34	307.15	0.003256	173.71	1.737e-07	0.24115	-0.61771
35	308.15	0.003245	188.52	1.885e-07	0.26171	-0.58218
36	309.15	0.003235	203.22	2.032e-07	0.28212	-0.54957
37	310.15	0.003224	218.11	2.181e-07	0.30279	-0.51886
38	311.15	0.003214	242.31	2.423e-07	0.33639	-0.47316

 

A plot of Log₁₀(vapor pressure (Pa)) versus reciprocal temperature (1/T (K)) for Run 2 gives the following statistical data using an unweighted least square treatment.

 

Slope:                                  -2.78 x 10³ 

Standard error in slope:       147

Intercept:                              8.43

Standard error in intercept: 0.482

 

The results obtained indicate the following vapour pressure relationship: 

Log₁₀(Vp (Pa)) = -2.78 x 10³ / temp (K) + 8.43

 

The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -0.883.

 

 

Run 3:

Table 3 - Vapor Pressure Data

Temperature (ºC)	Temperature (K)	Reciprocal Temperature (K^-1)	Mass Difference (µg)	Mass Difference (kg)	Vapor Pressure (Pa)	Log10 Vp
28	301.15	0.003321	126.95	1.270e-07	0.17624	-0.75390
29	302.15	0.003310	127.85	1.279e-07	0.17749	-0.75083
30	303.15	0.003299	132.23	1.322e-07	0.18357	-0.73620
31	304.15	0.003288	140.26	1.403e-07	0.19472	-0.71059
32	305.15	0.003277	149.92	1.499e-07	0.20813	-0.68167
33	306.15	0.003266	162.25	1.623e-07	0.22524	-0.64735
34	307.15	0.003256	172.80	1.728e-07	0.23989	-0.61999
35	308.15	0.003245	186.52	1.865e-07	0.25894	-0.58680
36	309.15	0.003235	206.65	2.067e-07	0.28688	-0.54230
37	310.15	0.003224	223.45	2.235e-07	0.31021	-0.50834
38	311.15	0.003214	239.44	2.394e-07	0.33240	-0.47834

 

A plot of Log₁₀(vapor pressure (Pa)) versus reciprocal temperature (1/T (K)) for Run 3 gives the following statistical data using an unweighted least square treatment.

 

Slope:                                  -2.74 x 10³ 

Standard error in slope:       147

Intercept:                              8.33

Standard error in intercept: 0.479

 

The results obtained indicate the following vapour pressure relationship: 

Log₁₀(Vp (Pa)) = -2.74 x 10³ / temp (K) + 8.33

 

The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -0.877.

 

Run 4:

Table 4 - Vapor Pressure Data

Temperature (ºC)	Temperature (K)	Reciprocal Temperature (K^-1)	Mass Difference (µg)	Mass Difference (kg)	Vapor Pressure (Pa)	Log10 Vp
28	301.15	0.003321	130.14	1.301e-07	0.18067	-0.74311
29	302.15	0.003310	128.88	1.289e-07	0.17892	-0.74734
30	303.15	0.003299	134.97	1.350e-07	0.18737	-0.72730
31	304.15	0.003288	142.26	1.423e-07	0.19749	-0.70445
32	305.15	0.003277	150.54	1.505e-07	0.20899	-0.67987
33	306.15	0.003266	164.95	1.650e-07	0.22899	-0.64018
34	307.15	0.003256	176.90	1.769e-07	0.24558	-0.60981
35	308.15	0.003245	188.96	1.890e-07	0.26232	-0.58117
36	309.15	0.003235	206.93	2.069e-07	0.28727	-0.54171
37	310.15	0.003224	224.88	2.249e-07	0.31219	-0.50558
38	311.15	0.003214	242.89	2.429e-07	0.33719	-0.47213

 

A plot of Log₁₀(vapor pressure (Pa)) versus reciprocal temperature (1/T (K)) for Run 4 gives the following statistical data using an unweighted least square treatment.

 

Slope:                                  -2.71 x 10³ 

Standard error in slope:       152

Intercept:                              8.21

Standard error in intercept: 0.496

 

The results obtained indicate the following vapour pressure relationship: 

Log₁₀(Vp (Pa)) = -2.71 x 10³ / temp (K) + 8.21

 

The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -0.868.

 

Run 5:

Table 5 - Vapor Pressure Data

Temperature (ºC)	Temperature (K)	Reciprocal Temperature (K^-1)	Mass Difference (µg)	Mass Difference (kg)	Vapor Pressure (Pa)	Log10 Vp
28	301.15	0.003321	127.43	1.274e-07	0.17691	-0.75225
29	302.15	0.003310	128.82	1.288e-07	0.17884	-0.74754
30	303.15	0.003299	134.10	1.341e-07	0.18617	-0.73009
31	304.15	0.003288	141.65	1.417e-07	0.19665	-0.70631
32	305.15	0.003277	151.16	1.512e-07	0.20985	-0.67809
33	306.15	0.003266	165.03	1.650e-07	0.22910	-0.63997
34	307.15	0.003256	175.22	1.752e-07	0.24325	-0.61395
35	308.15	0.003245	188.75	1.888e-07	0.26203	-0.58165
36	309.15	0.003235	205.23	2.052e-07	0.28491	-0.54529
37	310.15	0.003224	220.27	2.203e-07	0.30579	-0.51458
38	311.15	0.003214	239.60	2.396e-07	0.33263	-0.47804

 

A plot of Log₁₀(vapor pressure (Pa)) versus reciprocal temperature (1/T (K)) for Run 5 gives the following statistical data using an unweighted least square treatment.

Slope:                                  -2.69 x 10³ 

Standard error in slope:       124

Intercept:                              8.14

Standard error in intercept: 0.407

 

The results obtained indicate the following vapour pressure relationship: 

Log₁₀(Vp (Pa)) = -2.69 x 10³ / temp (K) + 8.14

 

The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -0.870.

 

Run 6:

Table 6 - Vapor Pressure Data

Temperature (ºC)	Temperature (K)	Reciprocal Temperature (K^-1)	Mass Difference (µg)	Mass Difference (kg)	Vapor Pressure (Pa)	Log10 Vp
28	301.15	0.003321	127.31	1.273e-07	0.17674	-0.75267
29	302.15	0.003310	128.22	1.282e-07	0.17800	-0.74958
30	303.15	0.003299	134.36	1.344e-07	0.18653	-0.72925
31	304.15	0.003288	138.32	1.383e-07	0.19202	-0.71665
32	305.15	0.003277	150.08	1.501e-07	0.20835	-0.68121
33	306.15	0.003266	163.59	1.636e-07	0.22710	-0.64378
34	307.15	0.003256	177.34	1.773e-07	0.24619	-0.60873
35	308.15	0.003245	189.02	1.890e-07	0.26241	-0.58102
36	309.15	0.003235	204.22	2.042e-07	0.28351	-0.54743
37	310.15	0.003224	221.42	2.214e-07	0.30739	-0.51231
38	311.15	0.003214	239.95	2.400e-07	0.33311	-0.47741

 

A plot of Log₁₀(vapor pressure (Pa)) versus reciprocal temperature (1/T (K)) for Run 6 gives the following statistical data using an unweighted least square treatment.

Slope:                                  -2.72 x 10³ 

Standard error in slope:       140

Intercept:                              8.26

Standard error in intercept: 0.458

 

The results obtained indicate the following vapour pressure relationship: 

Log₁₀(Vp (Pa)) = -2.72 x 10³ / temp (K) + 8.26

 

The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -0.874.

 

Run 7:

Table 7 - Vapor Pressure Data

Temperature (ºC)	Temperature (K)	Reciprocal Temperature (K^-1)	Mass Difference (µg)	Mass Difference (kg)	Vapor Pressure (Pa)	Log10 Vp
28	301.15	0.003321	126.18	1.262e-07	0.17517	-0.75654
29	302.15	0.003310	128.45	1.285e-07	0.17832	-0.74880
30	303.15	0.003299	132.99	1.330e-07	0.18462	-0.73372
31	304.15	0.003288	144.79	1.448e-07	0.20101	-0.69678
32	305.15	0.003277	153.13	1.531e-07	0.21258	-0.67248
33	306.15	0.003266	163.67	1.637e-07	0.22722	-0.64355
34	307.15	0.003256	175.49	1.755e-07	0.24363	-0.61327
35	308.15	0.003245	188.25	1.883e-07	0.26134	-0.58279
36	309.15	0.003235	205.05	2.051e-07	0.28466	-0.54567
37	310.15	0.003224	222.61	2.226e-07	0.30904	-0.50999
38	311.15	0.003214	241.46	2.415e-07	0.33521	-0.47468

 

A plot of Log₁₀(vapor pressure (Pa)) versus reciprocal temperature (1/T (K)) for Run 7 gives the following statistical data using an unweighted least square treatment.

Slope:                                  -2.73 x 10³ 

Standard error in slope:       115

Intercept:                              8.27

Standard error in intercept: 0.375

 

The results obtained indicate the following vapour pressure relationship: 

Log₁₀(Vp (Pa)) = -2.73 x 10³ / temp (K) + 8.27

 

The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -0.872.

 

Table 8 - Summary of Vapor Pressure Data

 

Run	Log10 [Vp(25 ºC)]
1	-0.910
2	-0.883
3	-0.877
4	-0.868
5	-0.870
6	-0.874
7	-0.872
Mean	-0.879

 

Conclusions:

The vapor pressure of the test item ST 04 C 21 has been determined to be 0.132 Pa at 25 ºC.

Executive summary:

The vapor pressure of the test item has been determined to be 0.132 Pa at 25 °C, using the vapor pressure balance method, designed to be compatible with Method A.4 Vapour Pressure of Commission Regulation (EC) No 440/2008 of 30 May 2008 and Method 104 of the OECD Guidelines for Testing of Chemicals, 23 March 2006 and OCSPP 830.7950 of the US EPA Office of Chemicals Safety and Pollution Prevention (OCSPP), Serie 830: Product Properties Test Guidelines. 

Description of key information

Weight of evidence : The substance vapour pressure is : 0.132 Pa at 25 °C (2021)

1. Vapour Pressure: 0.149 Pa at 25 °C, EU Method A.4 – vapour pressure balance method, 2019

2. Vapour Pressure: 0.132 Pa at 25 °C, EU Method A.4 – vapour pressure balance method, 2021

Key value for chemical safety assessment

Vapour pressure:

0.132 Pa

at the temperature of:

25 °C

Additional information

Key study 1: EU Method A.4, 2019 : The vapour pressure was determined using EU Method A.4 guideline using the vapour pressure balance method under GLP. Measurements being made at several temperatures and linear regression analysis used to calculate the vapour pressure at 25°C. The temperature of the sample was controlled electronically. The mass and temperature readings were recorded automatically into a computer file. The difference in mass readings with the orifice covered and uncovered is proportional to the vapour pressure at the given oven temperature. Temperature and pressure readings were taken between 25 and 35°C with a one-hour dwell time at 25°C between runs. The vapour pressure of the test item was extrapolated from the vapour pressure curve (log10Vpversus 1/T). The mean vapour pressure based on nine runs was 0.149 Pa at 25°C.

 

Key study 2: EU Method A.4, 2021 : The vapour pressure was determined using EU Method A.4 guideline using the vapour pressure balance method under GLP. Measurements being made at several temperatures and linear regression analysis used to calculate the vapour pressure at 25°C. The temperature of the sample was controlled electronically. The mass and temperature readings were recorded automatically into a computer file. The difference in mass readings with the orifice covered and uncovered is proportional to the vapour pressure at the given oven temperature. Temperature and pressure readings were taken between 28 and 38°C with a one-hour dwell time at 25°C between runs. The vapour pressure of the test item was extrapolated from the vapour pressure curve (log10Vpversus 1/T). The mean vapour pressure based on seven runs was 0.132 Pa at 25°C

Conclusion : the vapour pressure of the substance is 0.132 Pa at 25°C (2021)