Amines, C12-14-alkyl, isooctyl phosphates

Vapour pressure

Administrative data

Endpoint:

vapour pressure

Type of information:

experimental study

Adequacy of study:

key study

Study period:

The study was conducted between 12 September 2014 and 17 September 2014

Reliability:

1 (reliable without restriction)

Rationale for reliability incl. deficiencies:

guideline study

Remarks:

GLP guideline study

Data source

Reference

Reference Type:

study report

Title:

Unnamed

Year:

2015

Report date:

2015

Materials and methods

Test guideline

Test guideline 1

Qualifier:

according to guideline

Guideline:

OECD Guideline 104 (Vapour Pressure Curve)

Deviations:

no

Test guideline 2

Qualifier:

according to guideline

Guideline:

EU Method A.4 (Vapour Pressure)

Deviations:

no

GLP compliance:

yes (incl. QA statement)

Type of method:

effusion method: vapour pressure balance

Test material

Test material information

Constituent 1

Reference substance name:

Amines, C12-14-tert-alkyl, isooctyl mono phosphates

IUPAC Name:

Amines, C12-14-tert-alkyl, isooctyl mono phosphates

Constituent 2

Reference substance name:

Unknown, including minor amounts of diphosphate species, water. Possibly residual unreacted starting material and unknown byproducts.

IUPAC Name:

Unknown, including minor amounts of diphosphate species, water. Possibly residual unreacted starting material and unknown byproducts.

Test material form:

liquid: viscous

Results and discussion

Vapour pressure

Key result

Temp.:

25 °C

Vapour pressure:

0.069 Pa

Any other information on results incl. tables

Recorded temperatures, mass differences and the resulting calculated values of vapour pressure are shown in the following tables:

 

Run 1

Temperature (ºC)	Temperature (K)	Reciprocal Temperature (K^-1)	Mass Difference (µg)	Mass Difference (kg)	Vapor Pressure (Pa)	Log10Vp
30	303.15	0.003298697	86.60	8.660E-08	0.120222987	-0.920012487
31	304.15	0.003287851	91.89	9.189E-08	0.127566862	-0.894262127
32	305.15	0.003277077	99.39	9.939E-08	0.137978784	-0.860187688
33	306.15	0.003266373	105.57	1.056E-07	0.146558207	-0.833989857
34	307.15	0.003255738	113.43	1.134E-07	0.157469901	-0.802802447
35	308.15	0.003245173	123.34	1.233E-07	0.171227520	-0.766426435
36	309.15	0.003234676	132.17	1.322E-07	0.183485822	-0.736397489
37	310.15	0.003224246	141.26	1.413E-07	0.196105071	-0.707511177
38	311.15	0.003213884	149.97	1.500E-07	0.208196782	-0.681525987
39	312.15	0.003203588	161.18	1.612E-07	0.223759134	-0.650219227
40	313.15	0.003193358	173.40	1.734E-07	0.240723625	-0.618481286

A plot of Log₁₀(vapor pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 1 gives the following statistical data using an unweighted least squares treatment.

 

Slope:	-2.88 x 10^3
Standard error in slope:	24.4
Intercept:	8.58
Standard error in intercept:	7.93 x 10^-2

The results obtained indicate the following vapor pressure relationship:

 

Log₁₀(Vp (Pa)) = -2.88 x 10³/temp(K) + 8.58

 

The above yields a vapor pressure (Pa) at 298.15 K with a common logarithm of -1.08.

Run 2

Temperature (ºC)	Temperature (K)	Reciprocal Temperature (K^-1)	Mass Difference (µg)	Mass Difference (kg)	Vapor Pressure (Pa)	Log10Vp
30	303.15	0.003298697	78.82	7.882E-08	0.109422354	-0.960893948
31	304.15	0.003287851	83.09	8.309E-08	0.115350208	-0.937981620
32	305.15	0.003277077	91.45	9.145E-08	0.126956029	-0.896346669
33	306.15	0.003266373	98.19	9.819E-08	0.136312876	-0.865463119
34	307.15	0.003255738	106.99	1.070E-07	0.148529531	-0.828187191
35	308.15	0.003245173	116.04	1.160E-07	0.161093249	-0.792922659
36	309.15	0.003234676	124.44	1.244E-07	0.172754601	-0.762570376
37	310.15	0.003224246	134.41	1.344E-07	0.186595516	-0.729098798
38	311.15	0.003213884	144.16	1.442E-07	0.200131014	-0.698685605
39	312.15	0.003203588	155.44	1.554E-07	0.215790544	-0.665967591
40	313.15	0.003193358	165.68	1.657E-07	0.230006287	-0.638260293

A plot of Log₁₀(vapor pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 2 gives the following statistical data using an unweighted least squares treatment.

 

Slope:	-3.14 x 10^3
Standard error in slope:	32.1
Intercept:	9.38
Standard error in intercept:	0.104

The results obtained indicate the following vapor pressure relationship:

 

Log₁₀(Vp (Pa)) = -3.14 x 10³/temp(K) + 9.38

 

The above yields a vapor pressure (Pa) at 298.15 K with a common logarithm of -1.14.

Run 3

Temperature (ºC)	Temperature (K)	Reciprocal Temperature (K^-1)	Mass Difference (µg)	Mass Difference (kg)	Vapor Pressure (Pa)	Log10Vp
30	303.15	0.003298697	75.14	7.514E-08	0.104313571	-0.981659188
31	304.15	0.003287851	78.84	7.884E-08	0.109450119	-0.960783763
32	305.15	0.003277077	86.48	8.648E-08	0.120056396	-0.920614698
33	306.15	0.003266373	96.59	9.659E-08	0.134091666	-0.872598213
34	307.15	0.003255738	103.78	1.038E-07	0.144073228	-0.841416712
35	308.15	0.003245173	111.44	1.114E-07	0.154707271	-0.810489275
36	309.15	0.003234676	120.84	1.208E-07	0.167756879	-0.775319662
37	310.15	0.003224246	131.66	1.317E-07	0.182777811	-0.738076528
38	311.15	0.003213884	140.93	1.409E-07	0.195646946	-0.708526927
39	312.15	0.003203588	152.57	1.526E-07	0.211806248	-0.674061232
40	313.15	0.003193358	161.96	1.620E-07	0.224841974	-0.648122611

A plot of Log₁₀(vapor pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 3 gives the following statistical data using an unweighted least squares treatment.

 

Slope:	-3.27 x 10^3
Standard error in slope:	51.8
Intercept:	9.79
Standard error in intercept:	0.168

The results obtained indicate the following vapor pressure relationship:

 

Log₁₀(Vp (Pa)) = -3.27 x 10³/temp(K) + 9.79

 

The above yields a vapor pressure (Pa) at 298.15 K with a common logarithm of -1.17.

Run 4

Temperature (ºC)	Temperature (K)	Reciprocal Temperature (K^-1)	Mass Difference (µg)	Mass Difference (kg)	Vapor Pressure (Pa)	Log10Vp
30	303.15	0.003298697	76.19	7.619E-08	0.105771240	-0.975632405
31	304.15	0.003287851	80.04	8.004E-08	0.111116026	-0.954223299
32	305.15	0.003277077	85.07	8.507E-08	0.118098955	-0.927753946
33	306.15	0.003266373	92.81	9.281E-08	0.128844058	-0.889935606
34	307.15	0.003255738	101.98	1.020E-07	0.141574367	-0.849015371
35	308.15	0.003245173	109.37	1.094E-07	0.151833580	-0.818632167
36	309.15	0.003234676	118.53	1.185E-07	0.164550007	-0.783702094
37	310.15	0.003224246	127.01	1.270E-07	0.176322420	-0.753692463
38	311.15	0.003213884	136.54	1.365E-07	0.189552501	-0.722270480
39	312.15	0.003203588	146.64	1.466E-07	0.203573889	-0.691277927
40	313.15	0.003193358	157.19	1.572E-07	0.218219992	-0.661105465

A plot of Log₁₀(vapor pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 4 gives the following statistical data using an unweighted least squares treatment.

 

Slope:	-3.09 x 10^3
Standard error in slope:	46.5
Intercept:	9.20
Standard error in intercept:	0.151

The results obtained indicate the following vapor pressure relationship:

 

Log₁₀(Vp (Pa)) = -3.09 x 10³/temp(K) + 9.20

 

The above yields a vapor pressure (Pa) at 298.15 K with a common logarithm of -1.16.

Run 5

Temperature (ºC)	Temperature (K)	Reciprocal Temperature (K^-1)	Mass Difference (µg)	Mass Difference (kg)	Vapor Pressure (Pa)	Log10Vp
30	303.15	0.003298697	72.85	7.285E-08	0.101134464	-0.995100823
31	304.15	0.003287851	77.94	7.794E-08	0.108200688	-0.965769977
32	305.15	0.003277077	82.49	8.249E-08	0.114517254	-0.941129075
33	306.15	0.003266373	91.22	9.122E-08	0.126636730	-0.897440311
34	307.15	0.003255738	97.66	9.766E-08	0.135577100	-0.867813659
35	308.15	0.003245173	105.11	1.051E-07	0.145919609	-0.835886343
36	309.15	0.003234676	112.39	1.124E-07	0.156026114	-0.806802708
37	310.15	0.003224246	120.22	1.202E-07	0.166896160	-0.777553655
38	311.15	0.003213884	131.78	1.318E-07	0.182944402	-0.737680876
39	312.15	0.003203588	139.20	1.392E-07	0.193245263	-0.713891143
40	313.15	0.003193358	150.39	1.504E-07	0.208779850	-0.680311419

A plot of Log₁₀(vapor pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 5 gives the following statistical data using an unweighted least squares treatment.

 

Slope:	-3.01 x 10^3
Standard error in slope:	34.9
Intercept:	8.94
Standard error in intercept:	0.113

The results obtained indicate the following vapor pressure relationship:

 

Log₁₀(Vp (Pa)) = -3.01 x 10³/temp(K) + 8.94

 

The above yields a vapor pressure (Pa) at 298.15 K with a common logarithm of -1.17.

Run 6

Temperature (ºC)	Temperature (K)	Reciprocal Temperature (K^-1)	Mass Difference (µg)	Mass Difference (kg)	Vapor Pressure (Pa)	Log10Vp
30	303.15	0.003298697	67.77	6.777E-08	0.094082123	-1.026492893
31	304.15	0.003287851	73.64	7.364E-08	0.102231186	-0.990416599
32	305.15	0.003277077	78.26	7.826E-08	0.108644930	-0.963990535
33	306.15	0.003266373	85.01	8.501E-08	0.118015659	-0.928060363
34	307.15	0.003255738	92.45	9.245E-08	0.128344286	-0.891623463
35	308.15	0.003245173	99.51	9.951E-08	0.138145374	-0.859663652
36	309.15	0.003234676	106.76	1.068E-07	0.148210232	-0.829121814
37	310.15	0.003224246	114.67	1.147E-07	0.159191338	-0.798080566
38	311.15	0.003213884	126.39	1.264E-07	0.175461701	-0.755817665
39	312.15	0.003203588	135.57	1.356E-07	0.188205893	-0.725366783
40	313.15	0.003193358	145.89	1.459E-07	0.202532697	-0.693504854

A plot of Log₁₀(vapor pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 6 gives the following statistical data using an unweighted least squares treatment.

 

Slope:	-3.17 x 10^3
Standard error in slope:	30.3
Intercept:	9.42
Standard error in intercept:	9.83 x 10^-2

The results obtained indicate the following vapor pressure relationship:

 

Log₁₀(Vp (Pa)) = -3.17 x 10³/temp(K) + 9.42

 

The above yields a vapor pressure (Pa) at 298.15 K with a common logarithm of -1.20.

Run 7

Temperature (ºC)	Temperature (K)	Reciprocal Temperature (K^-1)	Mass Difference (µg)	Mass Difference (kg)	Vapor Pressure (Pa)	Log10Vp
30	303.15	0.003298697	68.61	6.861E-08	0.095248258	-1.021142959
31	304.15	0.003287851	71.58	7.158E-08	0.099371379	-1.002738685
32	305.15	0.003277077	76.92	7.692E-08	0.106784667	-0.971491103
33	306.15	0.003266373	82.71	8.271E-08	0.114822670	-0.939972358
34	307.15	0.003255738	91.29	9.129E-08	0.126733908	-0.897107172
35	308.15	0.003245173	98.95	9.895E-08	0.137367951	-0.862114580
36	309.15	0.003234676	106.79	1.068E-07	0.148251879	-0.828999792
37	310.15	0.003224246	114.62	1.146E-07	0.159121925	-0.798269975
38	311.15	0.003213884	123.82	1.238E-07	0.171893883	-0.764739579
39	312.15	0.003203588	132.07	1.321E-07	0.183346996	-0.736726201
40	313.15	0.003193358	141.72	1.417E-07	0.196743668	-0.706099235

A plot of Log₁₀(vapor pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 7 gives the following statistical data using an unweighted least squares treatment.

Slope:	-3.12 x 10^3
Standard error in slope:	52.5
Intercept:	9.25
Standard error in intercept:	0.170

 

The results obtained indicate the following vapor pressure relationship:

 

Log₁₀(Vp (Pa)) = -3.12 x 10³/temp(K) + 9.25

 

The above yields a vapor pressure (Pa) at 298.15 K with a common logarithm of -1.20.

Summary of Results

The values of vapor pressure at 25 °C extrapolated from each graph are summarized in the following table

Summary of Vapor Pressure Data

Run	Log10[Vp(25ºC)]
1	-1.08
2	-1.14
3	-1.17
4	-1.16
5	-1.17
6	-1.20
7	-1.20
Mean	-1.16
Vapor Pressure	6.92 x 10^-2Pa

The test item did not change in appearance under the conditions used in the determination.

Applicant's summary and conclusion

Conclusions:

The vapor pressure of the test item has been determined to be 6.9 x 10-2 Pa at 25 ºC.

Executive summary:

The vapor pressure of the test substance has been determined to be 6.9 x 10^-2 Pa at 25 °C, using the vapor pressure balance method, designed to be compatible with Method A4 Vapour Pressure of Commission Regulation (EC) No 440/2008 of 30 May 2008 and Method 104 of the OECD Guidelines for Testing of Chemicals, 23 March 2006.