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EC number: 700-485-5 | CAS number: 939402-02-5
Vapour pressure
Administrative data
- Endpoint:
- vapour pressure
- Type of information:
- experimental study
- Adequacy of study:
- key study
- Study period:
- 15th January 2010 to 23rd February 2010.
- Reliability:
- 1 (reliable without restriction)
- Rationale for reliability incl. deficiencies:
- other: Study conducted in compliance with agreed protocols, with no or minor deviations from standard test guidelines and/or minor methodological deficiencies, which do not affect the quality of the relevant results.
Data source
Reference
- Reference Type:
- study report
- Title:
- Unnamed
- Year:
- 2 010
Materials and methods
Test guideline
- Qualifier:
- according to guideline
- Guideline:
- EU Method A.4 (Vapour Pressure)
- Deviations:
- no
- GLP compliance:
- yes (incl. QA statement)
- Remarks:
- Date of inspection: 15/09/09 Date of Signature: 26/11/09
- Type of method:
- effusion method: vapour pressure balance
Test material
Reference
- Name:
- Unnamed
- Type:
- Constituent
- Details on test material:
- Sponsor's identification : DVS005u (aka Weston 705)
Description : clear colourless viscous liquid
Batch number : MW9F23A901
Date received : 05 November 2009
Expiry date : 15 June 2010
Storage conditions : approximately 4°C, under nitrogen, in the dark
Results and discussion
Vapour pressure
- Temp.:
- 25 °C
- Vapour pressure:
- 0 Pa
Transition / decomposition
- Transition / decomposition:
- no
Any other information on results incl. tables
Run1
Temperature (ºC) | Temperature (K) | Reciprocal Temperature (K-1) | Mass Difference (µg) | Mass Difference (kg) | Vapour Pressure (Pa) | Log10Vp |
175 | 448.15 | 0.002231396 | 380.86 | 3.809E-07 | 0.528731256 | -0.276765016 |
176 | 449.15 | 0.002226428 | 400.72 | 4.007E-07 | 0.556302024 | -0.254689360 |
177 | 450.15 | 0.002221482 | 431.72 | 4.317E-07 | 0.599337966 | -0.222328210 |
178 | 451.15 | 0.002216558 | 468.06 | 4.681E-07 | 0.649787196 | -0.187228850 |
179 | 452.15 | 0.002211655 | 491.85 | 4.919E-07 | 0.682813811 | -0.165697703 |
180 | 453.15 | 0.002206775 | 528.82 | 5.288E-07 | 0.734137643 | -0.134222507 |
181 | 454.15 | 0.002201916 | 567.99 | 5.680E-07 | 0.788515638 | -0.103189689 |
182 | 455.15 | 0.002197078 | 611.47 | 6.115E-07 | 0.848877018 | -0.071155224 |
183 | 456.15 | 0.002192261 | 667.44 | 6.674E-07 | 0.926577717 | -0.033118148 |
184 | 457.15 | 0.002187466 | 736.91 | 7.369E-07 | 1.023019875 | 0.009884071 |
185 | 458.15 | 0.002182691 | 804.02 | 8.040E-07 | 1.116185749 | 0.047736473 |
A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 1 gives the following statistical data using an unweighted least squares treatment.
Slope -6610.581
Standard deviation in slope 177.616
Intercept 14.462
Standard deviation in intercept 0.392
The results obtained indicate the following vapour pressure relationship:
Log10(Vp (Pa)) = -6610.581/temp(K) + 14.462
The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -7.710.
Run 1 - Graph of Log10Vapour Pressure vs Reciprocal Temperature see attached Run 1 to 9 - Graph of Log10 Vapour Pressure vs Reciprocal Temperature.
Run 2
Temperature (ºC) | Temperature (K) | Reciprocal Temperature (K-1) | Mass Difference (µg) | Mass Difference (kg) | Vapour Pressure (Pa) | Log10Vp |
175 | 448.15 | 0.002231396 | 383.13 | 3.831E-07 | 0.531882597 | -0.274184219 |
176 | 449.15 | 0.002226428 | 405.19 | 4.052E-07 | 0.562507529 | -0.249871660 |
177 | 450.15 | 0.002221482 | 438.63 | 4.386E-07 | 0.608930816 | -0.215432047 |
178 | 451.15 | 0.002216558 | 472.30 | 4.723E-07 | 0.655673403 | -0.183312433 |
179 | 452.15 | 0.002211655 | 509.04 | 5.090E-07 | 0.706677935 | -0.150778469 |
180 | 453.15 | 0.002206775 | 551.98 | 5.520E-07 | 0.766289656 | -0.115607037 |
181 | 454.15 | 0.002201916 | 598.44 | 5.984E-07 | 0.830788039 | -0.080509764 |
182 | 455.15 | 0.002197078 | 643.42 | 6.434E-07 | 0.893231803 | -0.049035822 |
183 | 456.15 | 0.002192261 | 698.68 | 6.987E-07 | 0.969946841 | -0.013252067 |
184 | 457.15 | 0.002187466 | 754.73 | 7.547E-07 | 1.047758601 | 0.020261235 |
185 | 458.15 | 0.002182691 | 805.20 | 8.052E-07 | 1.117823891 | 0.048373387 |
A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 2 gives the following statistical data using an unweighted least squares treatment.
Slope -6791.343
Standard deviation in slope 64.728
Intercept 14.873
Standard deviation in intercept 0.143
The results obtained indicate the following vapour pressure relationship:
Log10(Vp (Pa)) = -6791.343/temp(K) + 14.873
The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -7.905.
Run 2 - Graph of Log10Vapour Pressure vs Reciprocal Temperature see attached Run 1 to 9 - Graph of Log10 Vapour Pressure vs Reciprocal Temperature.
Run 3
Temperature (ºC) | Temperature (K) | Reciprocal Temperature (K-1) | Mass Difference (µg) | Mass Difference (kg) | Vapour Pressure (Pa) | Log10Vp |
175 | 448.15 | 0.002231396 | 382.98 | 3.830E-07 | 0.531674359 | -0.274354284 |
176 | 449.15 | 0.002226428 | 401.03 | 4.010E-07 | 0.556732383 | -0.254353516 |
177 | 450.15 | 0.002221482 | 434.39 | 4.344E-07 | 0.603044610 | -0.219650560 |
178 | 451.15 | 0.002216558 | 468.30 | 4.683E-07 | 0.650120378 | -0.187006221 |
179 | 452.15 | 0.002211655 | 505.04 | 5.050E-07 | 0.701124911 | -0.154204602 |
180 | 453.15 | 0.002206775 | 543.73 | 5.437E-07 | 0.754836543 | -0.122147083 |
181 | 454.15 | 0.002201916 | 577.17 | 5.772E-07 | 0.801259830 | -0.096226629 |
182 | 455.15 | 0.002197078 | 627.49 | 6.275E-07 | 0.871116882 | -0.059923570 |
183 | 456.15 | 0.002192261 | 682.83 | 6.828E-07 | 0.947942980 | -0.023217785 |
184 | 457.15 | 0.002187466 | 740.52 | 7.405E-07 | 1.028031480 | 0.012006414 |
185 | 458.15 | 0.002182691 | 782.83 | 7.828E-07 | 1.086768600 | 0.036137082 |
A plot of Log10 (vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 3 gives the following statistical data using an unweighted least squares treatment.
Slope -6568.269
Standard deviation in slope 92.203
Intercept 14.373
Standard deviation in intercept 0.203
The results obtained indicate the following vapour pressure relationship:
Log10(Vp (Pa)) = -6568.269/temp(K) + 14.373
The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -7.657.
Run 3 - Graph of Log10Vapour Pressure vs Reciprocal Temperature see attached Run 1 to 9 - Graph of Log10 Vapour Pressure vs Reciprocal Temperature.
Run 4
Temperature (ºC) | Temperature (K) | Reciprocal Temperature (K-1) | Mass Difference (µg) | Mass Difference (kg) | Vapour Pressure (Pa) | Log10Vp |
175 | 448.15 | 0.002231396 | 382.11 | 3.821E-07 | 0.530466576 | -0.275341975 |
176 | 449.15 | 0.002226428 | 401.97 | 4.020E-07 | 0.558037344 | -0.253336737 |
177 | 450.15 | 0.002221482 | 432.82 | 4.328E-07 | 0.600865048 | -0.221223058 |
178 | 451.15 | 0.002216558 | 456.13 | 4.561E-07 | 0.633225300 | -0.198441742 |
179 | 452.15 | 0.002211655 | 484.55 | 4.846E-07 | 0.672679541 | -0.172191781 |
180 | 453.15 | 0.002206775 | 525.68 | 5.257E-07 | 0.729778518 | -0.136808925 |
181 | 454.15 | 0.002201916 | 584.00 | 5.840E-07 | 0.810741620 | -0.091117532 |
182 | 455.15 | 0.002197078 | 639.73 | 6.397E-07 | 0.888109138 | -0.051533661 |
183 | 456.15 | 0.002192261 | 688.01 | 6.880E-07 | 0.955134147 | -0.019935628 |
184 | 457.15 | 0.002187466 | 736.52 | 7.365E-07 | 1.022478455 | 0.009654166 |
185 | 458.15 | 0.002182691 | 797.59 | 7.976E-07 | 1.107259261 | 0.044249322 |
A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 4 gives the following statistical data using an unweighted least squares treatment.
Slope -6770.783
Standard deviation in slope 187.810
Intercept 14.818
Standard deviation in intercept 0.414
The results obtained indicate the following vapour pressure relationship:
Log10(Vp (Pa)) = -6770.783/temp(K) + 14.818
The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -7.891.
Run 4 - Graph of Log10Vapour Pressure vs Reciprocal Temperature see attached Run 1 to 9 - Graph of Log10 Vapour Pressure vs Reciprocal Temperature.
Run 5
Temperature (ºC) | Temperature (K) | Reciprocal Temperature (K-1) | Mass Difference (µg) | Mass Difference (kg) | Vapour Pressure (Pa) | Log10Vp |
175 | 448.15 | 0.002231396 | 377.01 | 3.770E-07 | 0.523386469 | -0.281177509 |
176 | 449.15 | 0.002226428 | 401.03 | 4.010E-07 | 0.556732383 | -0.254353516 |
177 | 450.15 | 0.002221482 | 426.85 | 4.269E-07 | 0.592577158 | -0.227255093 |
178 | 451.15 | 0.002216558 | 460.14 | 4.601E-07 | 0.638792207 | -0.194640391 |
179 | 452.15 | 0.002211655 | 499.78 | 4.998E-07 | 0.693822683 | -0.158751506 |
180 | 453.15 | 0.002206775 | 535.88 | 5.359E-07 | 0.743938732 | -0.128462830 |
181 | 454.15 | 0.002201916 | 581.80 | 5.818E-07 | 0.807687456 | -0.092756662 |
182 | 455.15 | 0.002197078 | 625.52 | 6.255E-07 | 0.868382017 | -0.061289179 |
183 | 456.15 | 0.002192261 | 676.94 | 6.769E-07 | 0.939766151 | -0.026980202 |
184 | 457.15 | 0.002187466 | 733.14 | 7.331E-07 | 1.017786149 | 0.007656536 |
185 | 458.15 | 0.002182691 | 788.40 | 7.884E-07 | 1.094501187 | 0.039216237 |
A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 5 gives the following statistical data using an unweighted least squares treatment.
Slope -6687.856
Standard deviation in slope 78.723
Intercept 14.634
Standard deviation in intercept 0.174
The results obtained indicate the following vapour pressure relationship:
Log10(Vp (Pa)) = -6687.856/temp(K) + 14.634
The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -7.797.
Run 5 - Graph of Log10Vapour Pressure vs Reciprocal Temperature see attached Run 1 to 9 - Graph of Log10 Vapour Pressure vs Reciprocal Temperature.
Please note we have included runs 6,7 and 8 in the overall remarks section, please see these below:
Applicant's summary and conclusion
- Conclusions:
- The vapour pressure of the test material has been determined to be 1.6 x 10-8 Pa at 25ºC.
- Executive summary:
Method: The vapour pressure was determined using a vapour pressure balance with measurments being made at several temperatures and linear regression analysis used to calculate the vapour pressure at 25°C. Testing was conducted using Method 104 specified in the OECD Guidelines for Testing of Chemicals, 23 March 2006.
Summary of Results:
Run
Log10[Vp(25ºC)]
1
-7.710
2
-7.905
3
-7.657
4
-7.891
5
-7.797
6
-7.746
7
-7.623
8
-7.856
9
-7.876
Mean
-7.785
Vapour Pressure
1.6 x 10-8Pa
The test material did not change in appearance under the conditions used in the determination.
Conclusion:
The vapour pressure of the test material has been determined to be 1.6 x 10-8 Pa at 25ºC.
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