Phosphorous acid, mixed 2,4-bis(1,1-dimethylpropyl)phenyl and 4-(1,1-dimethylpropyl)phenyl triesters

Vapour pressure

Administrative data

Endpoint:

vapour pressure

Type of information:

experimental study

Adequacy of study:

key study

Study period:

15th January 2010 to 23rd February 2010.

Reliability:

1 (reliable without restriction)

Rationale for reliability incl. deficiencies:

other: Study conducted in compliance with agreed protocols, with no or minor deviations from standard test guidelines and/or minor methodological deficiencies, which do not affect the quality of the relevant results.

Data source

Reference

Reference Type:

study report

Title:

Unnamed

Year:

2010

Materials and methods

Test guideline

Qualifier:

according to guideline

Guideline:

EU Method A.4 (Vapour Pressure)

Deviations:

no

GLP compliance:

yes (incl. QA statement)

Remarks:

Date of inspection: 15/09/09 Date of Signature: 26/11/09

Type of method:

effusion method: vapour pressure balance

Test material

Test material information

Constituent 1

Reference substance name:

[4-(2-methylbutan-2-yl)phenyl]x[2,4-bis(2-methylbutan-2-yl)]3-x phosphite (where x = 0, 1, 2, 3)

IUPAC Name:

[4-(2-methylbutan-2-yl)phenyl]x[2,4-bis(2-methylbutan-2-yl)]3-x phosphite (where x = 0, 1, 2, 3)

Details on test material:

Sponsor's identification : DVS005u (aka Weston 705)
Description : clear colourless viscous liquid
Batch number : MW9F23A901
Date received : 05 November 2009
Expiry date : 15 June 2010
Storage conditions : approximately 4°C, under nitrogen, in the dark

Results and discussion

Vapour pressure

Temp.:

25 °C

Vapour pressure:

0 Pa

Transition / decomposition

Transition / decomposition:

no

Any other information on results incl. tables

Run1

Temperature (ºC)	Temperature (K)	Reciprocal Temperature (K^-1)	Mass Difference (µg)	Mass Difference (kg)	Vapour Pressure (Pa)	Log10Vp
175	448.15	0.002231396	380.86	3.809E-07	0.528731256	-0.276765016
176	449.15	0.002226428	400.72	4.007E-07	0.556302024	-0.254689360
177	450.15	0.002221482	431.72	4.317E-07	0.599337966	-0.222328210
178	451.15	0.002216558	468.06	4.681E-07	0.649787196	-0.187228850
179	452.15	0.002211655	491.85	4.919E-07	0.682813811	-0.165697703
180	453.15	0.002206775	528.82	5.288E-07	0.734137643	-0.134222507
181	454.15	0.002201916	567.99	5.680E-07	0.788515638	-0.103189689
182	455.15	0.002197078	611.47	6.115E-07	0.848877018	-0.071155224
183	456.15	0.002192261	667.44	6.674E-07	0.926577717	-0.033118148
184	457.15	0.002187466	736.91	7.369E-07	1.023019875	0.009884071
185	458.15	0.002182691	804.02	8.040E-07	1.116185749	0.047736473

A plot of Log₁₀(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 1 gives the following statistical data using an unweighted least squares treatment.

Slope                                       -6610.581
Standard deviation in slope     177.616

Intercept                                        14.462
Standard deviation in intercept    0.392

The results obtained indicate the following vapour pressure relationship:

Log₁₀(Vp (Pa)) = -6610.581/temp(K) + 14.462

The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -7.710.

Run 1 - Graph of Log₁₀Vapour Pressure vs Reciprocal Temperature see attached Run 1 to 9 - Graph of Log₁₀ Vapour Pressure vs Reciprocal Temperature.

Run 2

Temperature (ºC)	Temperature (K)	Reciprocal Temperature (K^-1)	Mass Difference (µg)	Mass Difference (kg)	Vapour Pressure (Pa)	Log10Vp
175	448.15	0.002231396	383.13	3.831E-07	0.531882597	-0.274184219
176	449.15	0.002226428	405.19	4.052E-07	0.562507529	-0.249871660
177	450.15	0.002221482	438.63	4.386E-07	0.608930816	-0.215432047
178	451.15	0.002216558	472.30	4.723E-07	0.655673403	-0.183312433
179	452.15	0.002211655	509.04	5.090E-07	0.706677935	-0.150778469
180	453.15	0.002206775	551.98	5.520E-07	0.766289656	-0.115607037
181	454.15	0.002201916	598.44	5.984E-07	0.830788039	-0.080509764
182	455.15	0.002197078	643.42	6.434E-07	0.893231803	-0.049035822
183	456.15	0.002192261	698.68	6.987E-07	0.969946841	-0.013252067
184	457.15	0.002187466	754.73	7.547E-07	1.047758601	0.020261235
185	458.15	0.002182691	805.20	8.052E-07	1.117823891	0.048373387

A plot of Log₁₀(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 2 gives the following statistical data using an unweighted least squares treatment.

Slope                                       -6791.343
Standard deviation in slope       64.728

Intercept                                        14.873
Standard deviation in intercept    0.143

The results obtained indicate the following vapour pressure relationship:

Log₁₀(Vp (Pa)) = -6791.343/temp(K) + 14.873

The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -7.905.

Run 2 - Graph of Log₁₀Vapour Pressure vs Reciprocal Temperature see attached Run 1 to 9 - Graph of Log₁₀ Vapour Pressure vs Reciprocal Temperature.

Run 3

Temperature (ºC)	Temperature (K)	Reciprocal Temperature (K^-1)	Mass Difference (µg)	Mass Difference (kg)	Vapour Pressure (Pa)	Log10Vp
175	448.15	0.002231396	382.98	3.830E-07	0.531674359	-0.274354284
176	449.15	0.002226428	401.03	4.010E-07	0.556732383	-0.254353516
177	450.15	0.002221482	434.39	4.344E-07	0.603044610	-0.219650560
178	451.15	0.002216558	468.30	4.683E-07	0.650120378	-0.187006221
179	452.15	0.002211655	505.04	5.050E-07	0.701124911	-0.154204602
180	453.15	0.002206775	543.73	5.437E-07	0.754836543	-0.122147083
181	454.15	0.002201916	577.17	5.772E-07	0.801259830	-0.096226629
182	455.15	0.002197078	627.49	6.275E-07	0.871116882	-0.059923570
183	456.15	0.002192261	682.83	6.828E-07	0.947942980	-0.023217785
184	457.15	0.002187466	740.52	7.405E-07	1.028031480	0.012006414
185	458.15	0.002182691	782.83	7.828E-07	1.086768600	0.036137082

A plot of Log₁₀ (vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 3 gives the following statistical data using an unweighted least squares treatment.

Slope                                       -6568.269
Standard deviation in slope       92.203

Intercept                                        14.373
Standard deviation in intercept    0.203

The results obtained indicate the following vapour pressure relationship:

Log₁₀(Vp (Pa)) = -6568.269/temp(K) + 14.373

The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -7.657.

Run 3 - Graph of Log₁₀Vapour Pressure vs Reciprocal Temperature see attached Run 1 to 9 - Graph of Log₁₀ Vapour Pressure vs Reciprocal Temperature.

Run 4

Temperature (ºC)	Temperature (K)	Reciprocal Temperature (K^-1)	Mass Difference (µg)	Mass Difference (kg)	Vapour Pressure (Pa)	Log10Vp
175	448.15	0.002231396	382.11	3.821E-07	0.530466576	-0.275341975
176	449.15	0.002226428	401.97	4.020E-07	0.558037344	-0.253336737
177	450.15	0.002221482	432.82	4.328E-07	0.600865048	-0.221223058
178	451.15	0.002216558	456.13	4.561E-07	0.633225300	-0.198441742
179	452.15	0.002211655	484.55	4.846E-07	0.672679541	-0.172191781
180	453.15	0.002206775	525.68	5.257E-07	0.729778518	-0.136808925
181	454.15	0.002201916	584.00	5.840E-07	0.810741620	-0.091117532
182	455.15	0.002197078	639.73	6.397E-07	0.888109138	-0.051533661
183	456.15	0.002192261	688.01	6.880E-07	0.955134147	-0.019935628
184	457.15	0.002187466	736.52	7.365E-07	1.022478455	0.009654166
185	458.15	0.002182691	797.59	7.976E-07	1.107259261	0.044249322

A plot of Log₁₀(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 4 gives the following statistical data using an unweighted least squares treatment.

Slope                                        -6770.783
Standard deviation in slope     187.810

Intercept                                        14.818
Standard deviation in intercept    0.414

The results obtained indicate the following vapour pressure relationship:

Log₁₀(Vp (Pa)) = -6770.783/temp(K) + 14.818

The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -7.891.

Run 4 - Graph of Log₁₀Vapour Pressure vs Reciprocal Temperature see attached Run 1 to 9 - Graph of Log₁₀ Vapour Pressure vs Reciprocal Temperature.

Run 5

Temperature (ºC)	Temperature (K)	Reciprocal Temperature (K^-1)	Mass Difference (µg)	Mass Difference (kg)	Vapour Pressure (Pa)	Log10Vp
175	448.15	0.002231396	377.01	3.770E-07	0.523386469	-0.281177509
176	449.15	0.002226428	401.03	4.010E-07	0.556732383	-0.254353516
177	450.15	0.002221482	426.85	4.269E-07	0.592577158	-0.227255093
178	451.15	0.002216558	460.14	4.601E-07	0.638792207	-0.194640391
179	452.15	0.002211655	499.78	4.998E-07	0.693822683	-0.158751506
180	453.15	0.002206775	535.88	5.359E-07	0.743938732	-0.128462830
181	454.15	0.002201916	581.80	5.818E-07	0.807687456	-0.092756662
182	455.15	0.002197078	625.52	6.255E-07	0.868382017	-0.061289179
183	456.15	0.002192261	676.94	6.769E-07	0.939766151	-0.026980202
184	457.15	0.002187466	733.14	7.331E-07	1.017786149	0.007656536
185	458.15	0.002182691	788.40	7.884E-07	1.094501187	0.039216237

A plot of Log₁₀(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 5 gives the following statistical data using an unweighted least squares treatment.

Slope                                       -6687.856
Standard deviation in slope       78.723

Intercept                                        14.634
Standard deviation in intercept    0.174

The results obtained indicate the following vapour pressure relationship:

Log₁₀(Vp (Pa)) = -6687.856/temp(K) + 14.634

The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -7.797.

Run 5 - Graph of Log₁₀Vapour Pressure vs Reciprocal Temperature see attached Run 1 to 9 - Graph of Log₁₀ Vapour Pressure vs Reciprocal Temperature.

Please note we have included runs 6,7 and 8 in the overall remarks section, please see these below:

Applicant's summary and conclusion

Conclusions:

The vapour pressure of the test material has been determined to be 1.6 x 10-8 Pa at 25ºC.

Executive summary:

Method: The vapour pressure was determined using a vapour pressure balance with measurments being made at several temperatures and linear regression analysis used to calculate the vapour pressure at 25°C. Testing was conducted using Method 104 specified in the OECD Guidelines for Testing of Chemicals, 23 March 2006.

Summary of Results:

Run	Log10[Vp(25ºC)]
1	-7.710
2	-7.905
3	-7.657
4	-7.891
5	-7.797
6	-7.746
7	-7.623
8	-7.856
9	-7.876
Mean	-7.785
Vapour Pressure	1.6 x 10^-8Pa

The test material did not change in appearance under the conditions used in the determination.

Conclusion:

The vapour pressure of the test material has been determined to be 1.6 x 10-8 Pa at 25ºC.