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Diss Factsheets

Administrative data

Endpoint:
vapour pressure
Type of information:
experimental study
Adequacy of study:
key study
Study period:
Testing was conducted between 15 September and 27 September 2010.
Reliability:
1 (reliable without restriction)
Rationale for reliability incl. deficiencies:
other: see 'Remark'
Remarks:
Study conducted in compliance with agreed protocols, with no or minor deviations from standard test guidelines and/or minor methodological deficiencies, which do not affect the quality of the relevant results. The study report was conclusive, done to a valid guideline and the study was conducted under GLP conditions.

Data source

Reference
Reference Type:
study report
Title:
Unnamed
Year:
2010

Materials and methods

Test guideline
Qualifier:
according to guideline
Guideline:
other: Testing was conducted using a procedure designed to be compatible with Method A4 Vapour Pressure of Commission Regulation (EC) No 440/2008 of 30 May 2008, and Method 104 specified in the OECD Guidelines for Testing of Chemicals, 23 March 2006.
Deviations:
no
GLP compliance:
yes (incl. QA statement)
Type of method:
effusion method: vapour pressure balance

Test material

Constituent 1
Reference substance name:
X-12764
IUPAC Name:
X-12764
Details on test material:
Sponsor's identification: X-12764
Description : dark brown viscous liquid
Batch number : not supplied
Label : INVENTORY NO: X-12764
Date received : 10 August 2010
Expiry date : 06 August 2016
Storage conditions: room temperature in the dark

Results and discussion

Vapour pressure
Temp.:
25 °C
Vapour pressure:
0.004 Pa
Transition / decomposition
Transition / decomposition:
no

Any other information on results incl. tables

Results

Run 1

Temperature (ºC)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass Difference (kg)

Vapour Pressure (Pa)

Log10Vp

47

320.15

0.003123536

20.77

2.077E-08

0.028834081

-1.540093882

48

321.15

0.003113810

22.17

2.217E-08

0.030777640

-1.511764686

49

322.15

0.003104144

29.15

2.915E-08

0.040467668

-1.392891820

50

323.15

0.003094538

31.05

3.105E-08

0.043105355

-1.365468774

51

324.15

0.003084992

29.95

2.995E-08

0.041578273

-1.381133552

52

325.15

0.003075504

38.14

3.814E-08

0.052948091

-1.276149690

53

326.15

0.003066074

37.44

3.744E-08

0.051976312

-1.284194539

54

327.15

0.003056702

42.63

4.263E-08

0.059181362

-1.227815046

55

328.15

0.003047387

45.33

4.533E-08

0.062929653

-1.201144660

56

329.15

0.003038129

47.13

4.713E-08

0.065428515

-1.184232939

57

330.15

0.003028926

52.22

5.222E-08

0.072494739

-1.139693511

A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 1 gives the following statistical data using an unweighted least squares treatment.

Slope                                       -4097.343
Standard deviation in slope     296.623

Intercept                                        11.284
Standard deviation in intercept    0.912

The results obtained indicate the following vapour pressure relationship:

Log10(Vp (Pa)) = -4097.343/temp(K) + 11.284

The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -2.459.


Run 2

Temperature (ºC)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass Difference (kg)

Vapour Pressure (Pa)

Log10Vp

47

320.15

0.003123536

20.07

2.007E-08

0.027862302

-1.554983006

48

321.15

0.003113810

25.66

2.566E-08

0.035622654

-1.448273727

49

322.15

0.003104144

28.95

2.895E-08

0.040190017

-1.395881811

50

323.15

0.003094538

29.65

2.965E-08

0.041161796

-1.385505681

51

324.15

0.003084992

34.65

3.465E-08

0.048103077

-1.317827140

52

325.15

0.003075504

35.84

3.584E-08

0.049755102

-1.303162378

53

326.15

0.003066074

38.54

3.854E-08

0.053503394

-1.271618668

54

327.15

0.003056702

43.43

4.343E-08

0.060291967

-1.219740549

55

328.15

0.003047387

43.73

4.373E-08

0.060708444

-1.216750901

56

329.15

0.003038129

49.22

4.922E-08

0.068329970

-1.165388769

57

330.15

0.003028926

50.02

5.002E-08

0.069440575

-1.158386691

A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 2 gives the following statistical data using an unweighted least squares treatment.

Slope                                       -3877.362
Standard deviation in slope     269.811

Intercept                                        10.613
Standard deviation in intercept    0.830

The results obtained indicate the following vapour pressure relationship:

Log10(Vp (Pa)) = -3877.362/temp(K) + 10.613

The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -2.391.


Run 3

Temperature (ºC)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass Difference (kg)

Vapour Pressure (Pa)

Log10Vp

47

320.15

0.003123536

21.27

2.127E-08

0.029528209

-1.529762889

48

321.15

0.003113810

23.86

2.386E-08

0.033123793

-1.479859939

49

322.15

0.003104144

29.15

2.915E-08

0.040467668

-1.392891820

50

323.15

0.003094538

30.25

3.025E-08

0.041994750

-1.376805000

51

324.15

0.003084992

35.14

3.514E-08

0.048783323

-1.311728622

52

325.15

0.003075504

38.24

3.824E-08

0.053086917

-1.275012495

53

326.15

0.003066074

36.54

3.654E-08

0.050726881

-1.294761836

54

327.15

0.003056702

41.73

4.173E-08

0.057931931

-1.237081994

55

328.15

0.003047387

44.93

4.493E-08

0.062374351

-1.204993960

56

329.15

0.003038129

47.63

4.763E-08

0.066122643

-1.179649797

57

330.15

0.003028926

50.02

5.002E-08

0.069440575

-1.158386691

A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 3 gives the following statistical data using an unweighted least squares treatment.

Slope                                       -3769.875
Standard deviation in slope     265.631

Intercept                                        10.283
Standard deviation in intercept    0.817

The results obtained indicate the following vapour pressure relationship:

Log10(Vp (Pa)) =-3769.875/temp(K) + 10.283

The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -2.362.


Run 4

Temperature (ºC)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass Difference (kg)

Vapour Pressure (Pa)

Log10Vp

47

320.15

0.003123536

20.47

2.047E-08

0.028417604

-1.546412536

48

321.15

0.003113810

24.16

2.416E-08

0.033540270

-1.474433449

49

322.15

0.003104144

26.86

2.686E-08

0.037288561

-1.428424370

50

323.15

0.003094538

30.75

3.075E-08

0.042688878

-1.369685259

51

324.15

0.003084992

31.25

3.125E-08

0.043383006

-1.362680357

52

325.15

0.003075504

33.55

3.355E-08

0.046575995

-1.331837854

53

326.15

0.003066074

36.04

3.604E-08

0.050032753

-1.300745596

54

327.15

0.003056702

40.34

4.034E-08

0.056002255

-1.251794485

55

328.15

0.003047387

42.73

4.273E-08

0.059320187

-1.226797486

56

329.15

0.003038129

47.33

4.733E-08

0.065706166

-1.182393874

57

330.15

0.003028926

49.62

4.962E-08

0.068885273

-1.161873619

A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 4 gives the following statistical data using an unweighted least squares treatment.

Slope                                       -3839.886
Standard deviation in slope     169.063

Intercept                                        10.480
Standard deviation in intercept    0.520

The results obtained indicate the following vapour pressure relationship:

Log10(Vp (Pa)) = -3839.886/temp(K) + 10.480

The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -2.399.


Run 5

Temperature (ºC)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass Difference (kg)

Vapour Pressure (Pa)

Log10Vp

47

320.15

0.003123536

21.87

2.187E-08

0.030361163

-1.517681596

48

321.15

0.003113810

26.46

2.646E-08

0.036733259

-1.434940539

49

322.15

0.003104144

29.85

2.985E-08

0.041439448

-1.382586043

50

323.15

0.003094538

28.26

2.826E-08

0.039232120

-1.406358221

51

324.15

0.003084992

34.25

3.425E-08

0.047547775

-1.322869803

52

325.15

0.003075504

34.15

3.415E-08

0.047408949

-1.324139671

53

326.15

0.003066074

35.44

3.544E-08

0.049199800

-1.308036666

54

327.15

0.003056702

40.84

4.084E-08

0.056696383

-1.246444645

55

328.15

0.003047387

44.23

4.423E-08

0.061402572

-1.211813439

56

329.15

0.003038129

45.53

4.553E-08

0.063207305

-1.199232728

57

330.15

0.003028926

50.92

5.092E-08

0.070690006

-1.150641984

A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 5 gives the following statistical data using an unweighted least squares treatment.

Slope                                       -3484.402
Standard deviation in slope     229.295

Intercept                                          9.399
Standard deviation in intercept    0.705

The results obtained indicate the following vapour pressure relationship:

Log10(Vp (Pa)) = -3484.402/temp(K) + 9.399

The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -2.288.

Please see Attachment 2 for Graphs of Log10Vapour Pressure vs Reciprocal Temperature Runs 1 - 5.

Applicant's summary and conclusion

Conclusions:
The vapour pressure of the test item has been determined to be 4.2 x 10e-3 Pa at 25ºC.
Executive summary:

INTRODUCTION

Hazardous physico-chemical properties of the test item have been determined.

Methods employed are designed to be compatible with those specified in Commission Regulation (EC) No 440/2008 of 30 May 2008, Part A: Methods for the determination of physico-chemical properties and the current OECD Guidelines for Testing of Chemicals.

Method

The vapour pressure was determined using a vapour pressure balance withasurents being made at several temperatures and linear regression analysis used to calculate the vapour pressure at 25°C. Testing was conducted using a procedure designed to be compatible with Method A4 Vapour Pressure of Commission Regulation (EC) No 440/2008 of 30 May 2008, and Method 104 specified in the OECD Guidelines for Testing of Chemicals, 23 March 2006.

Summary of Results

Run

Log10[Vp(25ºC)]

1

-2.459

2

-2.391

3

-2.361

4

-2.399

5

-2.288

Mean

-2.380

Vapour Pressure

4.169 x 10-3Pa

Conclusion

The vapour pressure of the test item has been determined to be 4.2 x 10-3Pa at 25ºC.