Registration Dossier

Administrative data

Endpoint:
vapour pressure
Type of information:
experimental study
Adequacy of study:
key study
Study period:
The study was conducted between 12 September 2014 and 17 September 2014
Reliability:
1 (reliable without restriction)
Rationale for reliability incl. deficiencies:
guideline study
Remarks:
GLP guideline study

Data source

Reference
Reference Type:
study report
Title:
Unnamed
Year:
2015
Report Date:
2015

Materials and methods

Test guidelineopen allclose all
Qualifier:
according to
Guideline:
OECD Guideline 104 (Vapour Pressure Curve)
Deviations:
no
Qualifier:
according to
Guideline:
EU Method A.4 (Vapour Pressure)
Deviations:
no
GLP compliance:
yes (incl. certificate)
Type of method:
effusion method: vapour pressure balance

Test material

Reference
Name:
Unnamed
Type:
Constituent
Type:
Constituent
Test material form:
liquid: viscous

Results and discussion

Vapour pressure
Key result
Temp.:
25 °C
Vapour pressure:
0.069 Pa

Any other information on results incl. tables

Recorded temperatures, mass differences and the resulting calculated values of vapour pressure are shown in the following tables:

 

Run 1

Temperature (ºC)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass Difference (kg)

Vapor Pressure (Pa)

Log10Vp

30

303.15

0.003298697

86.60

8.660E-08

0.120222987

-0.920012487

31

304.15

0.003287851

91.89

9.189E-08

0.127566862

-0.894262127

32

305.15

0.003277077

99.39

9.939E-08

0.137978784

-0.860187688

33

306.15

0.003266373

105.57

1.056E-07

0.146558207

-0.833989857

34

307.15

0.003255738

113.43

1.134E-07

0.157469901

-0.802802447

35

308.15

0.003245173

123.34

1.233E-07

0.171227520

-0.766426435

36

309.15

0.003234676

132.17

1.322E-07

0.183485822

-0.736397489

37

310.15

0.003224246

141.26

1.413E-07

0.196105071

-0.707511177

38

311.15

0.003213884

149.97

1.500E-07

0.208196782

-0.681525987

39

312.15

0.003203588

161.18

1.612E-07

0.223759134

-0.650219227

40

313.15

0.003193358

173.40

1.734E-07

0.240723625

-0.618481286

A plot of Log10(vapor pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 1 gives the following statistical data using an unweighted least squares treatment.

 

Slope:

-2.88 x 103

Standard error in slope:

24.4

Intercept:

8.58

Standard error in intercept:

7.93 x 10-2

The results obtained indicate the following vapor pressure relationship:

 

Log10(Vp (Pa)) = -2.88 x 103/temp(K) + 8.58

 

The above yields a vapor pressure (Pa) at 298.15 K with a common logarithm of -1.08.

Run 2

Temperature (ºC)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass Difference (kg)

Vapor Pressure (Pa)

Log10Vp

30

303.15

0.003298697

78.82

7.882E-08

0.109422354

-0.960893948

31

304.15

0.003287851

83.09

8.309E-08

0.115350208

-0.937981620

32

305.15

0.003277077

91.45

9.145E-08

0.126956029

-0.896346669

33

306.15

0.003266373

98.19

9.819E-08

0.136312876

-0.865463119

34

307.15

0.003255738

106.99

1.070E-07

0.148529531

-0.828187191

35

308.15

0.003245173

116.04

1.160E-07

0.161093249

-0.792922659

36

309.15

0.003234676

124.44

1.244E-07

0.172754601

-0.762570376

37

310.15

0.003224246

134.41

1.344E-07

0.186595516

-0.729098798

38

311.15

0.003213884

144.16

1.442E-07

0.200131014

-0.698685605

39

312.15

0.003203588

155.44

1.554E-07

0.215790544

-0.665967591

40

313.15

0.003193358

165.68

1.657E-07

0.230006287

-0.638260293

A plot of Log10(vapor pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 2 gives the following statistical data using an unweighted least squares treatment.

 

Slope:

-3.14 x 103

Standard error in slope:

32.1

Intercept:

9.38

Standard error in intercept:

0.104

The results obtained indicate the following vapor pressure relationship:

 

Log10(Vp (Pa)) = -3.14 x 103/temp(K) + 9.38

 

The above yields a vapor pressure (Pa) at 298.15 K with a common logarithm of -1.14.

Run 3

Temperature (ºC)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass Difference (kg)

Vapor Pressure (Pa)

Log10Vp

30

303.15

0.003298697

75.14

7.514E-08

0.104313571

-0.981659188

31

304.15

0.003287851

78.84

7.884E-08

0.109450119

-0.960783763

32

305.15

0.003277077

86.48

8.648E-08

0.120056396

-0.920614698

33

306.15

0.003266373

96.59

9.659E-08

0.134091666

-0.872598213

34

307.15

0.003255738

103.78

1.038E-07

0.144073228

-0.841416712

35

308.15

0.003245173

111.44

1.114E-07

0.154707271

-0.810489275

36

309.15

0.003234676

120.84

1.208E-07

0.167756879

-0.775319662

37

310.15

0.003224246

131.66

1.317E-07

0.182777811

-0.738076528

38

311.15

0.003213884

140.93

1.409E-07

0.195646946

-0.708526927

39

312.15

0.003203588

152.57

1.526E-07

0.211806248

-0.674061232

40

313.15

0.003193358

161.96

1.620E-07

0.224841974

-0.648122611

A plot of Log10(vapor pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 3 gives the following statistical data using an unweighted least squares treatment.

 

Slope:

-3.27 x 103

Standard error in slope:

51.8

Intercept:

9.79

Standard error in intercept:

0.168

The results obtained indicate the following vapor pressure relationship:

 

Log10(Vp (Pa)) = -3.27 x 103/temp(K) + 9.79

 

The above yields a vapor pressure (Pa) at 298.15 K with a common logarithm of -1.17.

Run 4

Temperature (ºC)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass Difference (kg)

Vapor Pressure (Pa)

Log10Vp

30

303.15

0.003298697

76.19

7.619E-08

0.105771240

-0.975632405

31

304.15

0.003287851

80.04

8.004E-08

0.111116026

-0.954223299

32

305.15

0.003277077

85.07

8.507E-08

0.118098955

-0.927753946

33

306.15

0.003266373

92.81

9.281E-08

0.128844058

-0.889935606

34

307.15

0.003255738

101.98

1.020E-07

0.141574367

-0.849015371

35

308.15

0.003245173

109.37

1.094E-07

0.151833580

-0.818632167

36

309.15

0.003234676

118.53

1.185E-07

0.164550007

-0.783702094

37

310.15

0.003224246

127.01

1.270E-07

0.176322420

-0.753692463

38

311.15

0.003213884

136.54

1.365E-07

0.189552501

-0.722270480

39

312.15

0.003203588

146.64

1.466E-07

0.203573889

-0.691277927

40

313.15

0.003193358

157.19

1.572E-07

0.218219992

-0.661105465

A plot of Log10(vapor pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 4 gives the following statistical data using an unweighted least squares treatment.

 

Slope:

-3.09 x 103

Standard error in slope:

46.5

Intercept:

9.20

Standard error in intercept:

0.151

The results obtained indicate the following vapor pressure relationship:

 

Log10(Vp (Pa)) = -3.09 x 103/temp(K) + 9.20

 

The above yields a vapor pressure (Pa) at 298.15 K with a common logarithm of -1.16.

Run 5

Temperature (ºC)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass Difference (kg)

Vapor Pressure (Pa)

Log10Vp

30

303.15

0.003298697

72.85

7.285E-08

0.101134464

-0.995100823

31

304.15

0.003287851

77.94

7.794E-08

0.108200688

-0.965769977

32

305.15

0.003277077

82.49

8.249E-08

0.114517254

-0.941129075

33

306.15

0.003266373

91.22

9.122E-08

0.126636730

-0.897440311

34

307.15

0.003255738

97.66

9.766E-08

0.135577100

-0.867813659

35

308.15

0.003245173

105.11

1.051E-07

0.145919609

-0.835886343

36

309.15

0.003234676

112.39

1.124E-07

0.156026114

-0.806802708

37

310.15

0.003224246

120.22

1.202E-07

0.166896160

-0.777553655

38

311.15

0.003213884

131.78

1.318E-07

0.182944402

-0.737680876

39

312.15

0.003203588

139.20

1.392E-07

0.193245263

-0.713891143

40

313.15

0.003193358

150.39

1.504E-07

0.208779850

-0.680311419

A plot of Log10(vapor pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 5 gives the following statistical data using an unweighted least squares treatment.

 

Slope:

-3.01 x 103

Standard error in slope:

34.9

Intercept:

8.94

Standard error in intercept:

0.113

The results obtained indicate the following vapor pressure relationship:

 

Log10(Vp (Pa)) = -3.01 x 103/temp(K) + 8.94

 

The above yields a vapor pressure (Pa) at 298.15 K with a common logarithm of -1.17.

Run 6

Temperature (ºC)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass Difference (kg)

Vapor Pressure (Pa)

Log10Vp

30

303.15

0.003298697

67.77

6.777E-08

0.094082123

-1.026492893

31

304.15

0.003287851

73.64

7.364E-08

0.102231186

-0.990416599

32

305.15

0.003277077

78.26

7.826E-08

0.108644930

-0.963990535

33

306.15

0.003266373

85.01

8.501E-08

0.118015659

-0.928060363

34

307.15

0.003255738

92.45

9.245E-08

0.128344286

-0.891623463

35

308.15

0.003245173

99.51

9.951E-08

0.138145374

-0.859663652

36

309.15

0.003234676

106.76

1.068E-07

0.148210232

-0.829121814

37

310.15

0.003224246

114.67

1.147E-07

0.159191338

-0.798080566

38

311.15

0.003213884

126.39

1.264E-07

0.175461701

-0.755817665

39

312.15

0.003203588

135.57

1.356E-07

0.188205893

-0.725366783

40

313.15

0.003193358

145.89

1.459E-07

0.202532697

-0.693504854

A plot of Log10(vapor pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 6 gives the following statistical data using an unweighted least squares treatment.

 

Slope:

-3.17 x 103

Standard error in slope:

30.3

Intercept:

9.42

Standard error in intercept:

9.83 x 10-2

The results obtained indicate the following vapor pressure relationship:

 

Log10(Vp (Pa)) = -3.17 x 103/temp(K) + 9.42

 

The above yields a vapor pressure (Pa) at 298.15 K with a common logarithm of -1.20.

Run 7

Temperature (ºC)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass Difference (kg)

Vapor Pressure (Pa)

Log10Vp

30

303.15

0.003298697

68.61

6.861E-08

0.095248258

-1.021142959

31

304.15

0.003287851

71.58

7.158E-08

0.099371379

-1.002738685

32

305.15

0.003277077

76.92

7.692E-08

0.106784667

-0.971491103

33

306.15

0.003266373

82.71

8.271E-08

0.114822670

-0.939972358

34

307.15

0.003255738

91.29

9.129E-08

0.126733908

-0.897107172

35

308.15

0.003245173

98.95

9.895E-08

0.137367951

-0.862114580

36

309.15

0.003234676

106.79

1.068E-07

0.148251879

-0.828999792

37

310.15

0.003224246

114.62

1.146E-07

0.159121925

-0.798269975

38

311.15

0.003213884

123.82

1.238E-07

0.171893883

-0.764739579

39

312.15

0.003203588

132.07

1.321E-07

0.183346996

-0.736726201

40

313.15

0.003193358

141.72

1.417E-07

0.196743668

-0.706099235

A plot of Log10(vapor pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 7 gives the following statistical data using an unweighted least squares treatment.

Slope:

-3.12 x 103

Standard error in slope:

52.5

Intercept:

9.25

Standard error in intercept:

0.170

 

The results obtained indicate the following vapor pressure relationship:

 

Log10(Vp (Pa)) = -3.12 x 103/temp(K) + 9.25

 

The above yields a vapor pressure (Pa) at 298.15 K with a common logarithm of -1.20.

Summary of Results

The values of vapor pressure at 25 °C extrapolated from each graph are summarized in the following table

Summary of Vapor Pressure Data

Run

Log10[Vp(25ºC)]

1

-1.08

2

-1.14

3

-1.17

4

-1.16

5

-1.17

6

-1.20

7

-1.20

Mean

-1.16

Vapor Pressure

6.92 x 10-2Pa

The test item did not change in appearance under the conditions used in the determination.

Applicant's summary and conclusion

Conclusions:
The vapor pressure of the test item has been determined to be 6.9 x 10-2 Pa at 25 ºC.
Executive summary:

The vapor pressure of the test substance has been determined to be 6.9 x 10-2 Pa at 25 °C, using the vapor pressure balance method, designed to be compatible with Method A4 Vapour Pressure of Commission Regulation (EC) No 440/2008 of 30 May 2008 and Method 104 of the OECD Guidelines for Testing of Chemicals, 23 March 2006.