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Administrative data

Endpoint:
vapour pressure
Type of information:
experimental study
Adequacy of study:
key study
Study period:
Testing was conducted between 15 April 2010 and 07 May 2010.
Reliability:
1 (reliable without restriction)
Rationale for reliability incl. deficiencies:
other: see 'Remark'
Remarks:
Study conducted in compliance with agreed protocols, with no or minor deviations from standard test guidelines and/or minor methodological deficiencies, which do not affect the quality of the relevant results. The study report was conclusive, done to a valid guideline and the study was conducted under GLP conditions.

Data source

Reference
Reference Type:
study report
Title:
Unnamed
Year:
2010
Report date:
2010

Materials and methods

Test guideline
Qualifier:
according to guideline
Guideline:
EU Method A.4 (Vapour Pressure)
Deviations:
no
GLP compliance:
yes (incl. QA statement)
Type of method:
effusion method: vapour pressure balance

Test material

Constituent 1
Reference substance name:
SULFOCLOR LF 1013
IUPAC Name:
SULFOCLOR LF 1013
Constituent 2
Reference substance name:
Paraffin waxes and Hydrocarbon waxes, chloro, sulfochlorinated
EC Number:
269-145-7
EC Name:
Paraffin waxes and Hydrocarbon waxes, chloro, sulfochlorinated
Cas Number:
68188-19-2
Molecular formula:
CnHxCly(SO2Cl)z n= 14 - 17 or n=17 - 30 ; x=2n+2-y-z
IUPAC Name:
Paraffin waxes and Hydrocarbon waxes, chloro, sulfochlorinated
Details on test material:
Sponsor's identification: SULFOCLOR LF 1013
CAS No : 68188-19-2
Description : pale yellow slightly viscous liquid
Purity : >99%
Batch number: None supplied
Label : Sulfoclor LF 1013 TANQUE 25.09.2009
Date received: 05 February 2010
Expiry date : 23 September 2010
Storage conditions: room temperature in the dark

Results and discussion

Vapour pressure
Temp.:
25 °C
Vapour pressure:
0.001 Pa
Transition / decomposition
Transition / decomposition:
no

Any other information on results incl. tables

Results

Run1

Temperature (ºC)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass Difference (kg)

Vapour Pressure (Pa)

Log10Vp

66

339.15

0.002948548

69.89

6.989E-08

0.097025226

-1.013115338

67

340.15

0.002939879

74.88

7.488E-08

0.103952624

-0.983164543

68

341.15

0.002931262

80.67

8.067E-08

0.111990628

-0.950818322

69

342.15

0.002922695

88.06

8.806E-08

0.122249841

-0.912751698

70

343.15

0.002914177

97.75

9.775E-08

0.135702043

-0.867413613

71

344.15

0.002905710

105.93

1.059E-07

0.147057979

-0.832511406

72

345.15

0.002897291

116.82

1.168E-07

0.162176089

-0.790013177

73

346.15

0.002888921

133.89

1.339E-07

0.185873622

-0.730782237

74

347.15

0.002880599

140.88

1.409E-07

0.195577533

-0.708681036

75

348.15

0.002872325

155.76

1.558E-07

0.216234785

-0.665074440

A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 1 gives the following statistical data using an unweighted least squares treatment.

Slope                                        -4691.089
Standard deviation in slope      113.046

Intercept                                        12.806
Standard deviation in intercept     0.329

The results obtained indicate the following vapour pressure relationship:

Log10(Vp (Pa)) = -4691.089 /temp(K) + 12.086

The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -2.928.

Run 2

Temperature (ºC)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass Difference (kg)

Vapour Pressure (Pa)

Log10Vp

66

339.15

0.002948548

68.89

6.889E-08

0.095636970

-1.019374194

67

340.15

0.002939879

76.48

7.648E-08

0.106173834

-0.973982499

68

341.15

0.002931262

80.37

8.037E-08

0.111574151

-0.952436410

69

342.15

0.002922695

86.76

8.676E-08

0.120445108

-0.919210835

70

343.15

0.002914177

95.35

9.535E-08

0.132370229

-0.878209681

71

344.15

0.002905710

107.63

1.076E-07

0.149418015

-0.825597038

72

345.15

0.002897291

121.41

1.214E-07

0.168548185

-0.773275920

73

346.15

0.002888921

127.50

1.275E-07

0.177002665

-0.752020194

74

347.15

0.002880599

138.88

1.389E-07

0.192801021

-0.714890671

75

348.15

0.002872325

150.96

1.510E-07

0.209571156

-0.678668492

A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 2 gives the following statistical data using an unweighted least squares treatment.

Slope                                       -4559.896
Standard deviation in slope      128.286

Intercept                                        12.421
Standard deviation in intercept     0.373

The results obtained indicate the following vapour pressure relationship:

Log10(Vp (Pa)) = -4559.896 /temp(K) + 12.421

The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -2.873.

Run 3

Temperature (ºC)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass Difference (kg)

Vapour Pressure (Pa)

Log10Vp

66

339.15

0.002948548

64.70

6.470E-08

0.089820176

-1.046626098

67

340.15

0.002939879

68.69

6.869E-08

0.095359318

-1.020636862

68

341.15

0.002931262

73.88

7.388E-08

0.102564368

-0.989003492

69

342.15

0.002922695

80.47

8.047E-08

0.111712976

-0.951896377

70

343.15

0.002914177

89.46

8.946E-08

0.124193400

-0.905901485

71

344.15

0.002905710

96.45

9.645E-08

0.133897310

-0.873228147

72

345.15

0.002897291

106.23

1.062E-07

0.147474456

-0.831283197

73

346.15

0.002888921

116.32

1.163E-07

0.161481961

-0.791875985

74

347.15

0.002880599

130.20

1.302E-07

0.180750957

-0.742919394

75

348.15

0.002872325

140.68

1.407E-07

0.195299882

-0.709298019

A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 3 gives the following statistical data using an unweighted least squares treatment.

Slope                                       -4549.776
Standard deviation in slope      102.515

Intercept                                       12.354
Standard deviation in intercept     0.298

The results obtained indicate the following vapour pressure relationship:

Log10(Vp (Pa)) = -4549.776 /temp(K) + 12.354

The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -2.906.

Run 4

Temperature (ºC)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass Difference (kg)

Vapour Pressure (Pa)

Log10Vp

66

339.15

0.002948548

63.20

6.320E-08

0.087737792

-1.056813300

67

340.15

0.002939879

67.19

6.719E-08

0.093276934

-1.030225738

68

341.15

0.002931262

71.99

7.199E-08

0.099940564

-1.000258205

69

342.15

0.002922695

77.48

7.748E-08

0.107562090

-0.968340767

70

343.15

0.002914177

84.77

8.477E-08

0.117682478

-0.929288196

71

344.15

0.002905710

98.15

9.815E-08

0.136257346

-0.865640075

72

345.15

0.002897291

102.34

1.023E-07

0.142074139

-0.847484966

73

346.15

0.002888921

113.92

1.139E-07

0.158150146

-0.800930402

74

347.15

0.002880599

122.51

1.225E-07

0.170075267

-0.769358839

75

348.15

0.002872325

139.28

1.393E-07

0.193356323

-0.713641621

A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 4 gives the following statistical data using an unweighted least squares treatment.

Slope                                       -4533.377
Standard deviation in slope     148.081

Intercept                                        12.295
Standard deviation in intercept    0.431

The results obtained indicate the following vapour pressure relationship:

Log10(Vp (Pa)) = -4533.377 /temp(K) + 12.295

The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -2.910.

Run 5

Temperature (ºC)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass Difference (kg)

Vapour Pressure (Pa)

Log10Vp

66

339.15

0.002948548

60.01

6.001E-08

0.083309254

-1.079306752

67

340.15

0.002939879

64.50

6.450E-08

0.089542525

-1.047970664

68

341.15

0.002931262

69.69

6.969E-08

0.096747574

-1.014359914

69

342.15

0.002922695

75.58

7.558E-08

0.104924403

-0.979123491

70

343.15

0.002914177

82.37

8.237E-08

0.114350663

-0.941761313

71

344.15

0.002905710

90.86

9.086E-08

0.126136958

-0.899157646

72

345.15

0.002897291

99.74

9.974E-08

0.138464673

-0.858661015

73

346.15

0.002888921

109.83

1.098E-07

0.152472178

-0.816809395

74

347.15

0.002880599

119.81

1.198E-07

0.166326975

-0.779037311

75

348.15

0.002872325

132.29

1.323E-07

0.183652413

-0.736003362

A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 5 gives the following statistical data using an unweighted least squares treatment.

Slope                                       -4552.739
Standard deviation in slope        82.290

Intercept                                       12.334
Standard deviation in intercept     0.293

The results obtained indicate the following vapour pressure relationship:

Log10(Vp (Pa)) = -4552.739 /temp(K) + 12.334

The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -2.936.

Run 6

Temperature (ºC)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass Difference (kg)

Vapour Pressure (Pa)

Log10Vp

66

339.15

0.002948548

59.01

5.901E-08

0.081920998

-1.086604764

67

340.15

0.002939879

62.80

6.280E-08

0.087182489

-1.059570735

68

341.15

0.002931262

67.59

6.759E-08

0.093832236

-1.027647932

69

342.15

0.002922695

74.18

7.418E-08

0.102980845

-0.987243550

70

343.15

0.002914177

80.77

8.077E-08

0.112129453

-0.950280296

71

344.15

0.002905710

91.56

9.156E-08

0.127108738

-0.895824595

72

345.15

0.002897291

95.85

9.585E-08

0.133064357

-0.875938262

73

346.15

0.002888921

111.62

1.116E-07

0.154957157

-0.809788361

74

347.15

0.002880599

119.91

1.199E-07

0.166465801

-0.778674976

75

348.15

0.002872325

129.00

1.290E-07

0.179085050

-0.746940668

A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 6 gives the following statistical data using an unweighted least squares treatment.

Slope                                       -4650.943
Standard deviation in slope      132.149

Intercept                                        12.613
Standard deviation in intercept     0.385

The results obtained indicate the following vapour pressure relationship:

Log10(Vp (Pa)) = -4650.943 /temp(K) + 12.613

The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -2.986.

Please see Attachment 3 for Graphs of Log10 Vapour Pressure vs Reciprocal Temperature Runs 1 - 6

Summary of Results

Run

Log10[Vp(25ºC)]

1

-2.928

2

-2.873

3

-2.906

4

-2.910

5

-2.936

6

-2.986

Mean

-2.923

Vapour Pressure

1.2 x 10-3Pa

The test item did not change in appearance under the conditions used in the determination.

Applicant's summary and conclusion

Conclusions:
The vapour pressure of Sulfoclor LF 1013 has been determined to be 1.2 x 10E-3 Pa at 25ºC
Executive summary:

The hazardous physico-chemical properties of Sulfoclor LF 1013 have been determined. Methods employed were compatible with those detailed in Commission Regulation (EC) No 440/2008 of 30 May 2008, Part A: Methods for the determination of physico-chemical properties.

Method                   

The vapour pressure was determined using a vapour pressure balance, with measurents being made at several temperatures and linear regression analysis used to calculate the vapour pressure at 25°C. The method employed was designed to be compatible with Method A4 Vapour Pressure of Commission Regulation (EC) No 440/2008 of 30 May 2008.

Conclusion                      

The vapour pressure of Sulfoclor LF 1013 has been determined to be 1.2 x 10-3 Pa at 25ºC.

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