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Vapour pressure

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Reference
Endpoint:
vapour pressure
Type of information:
experimental study
Adequacy of study:
key study
Study period:
17 May 2010 and 05 June 2010
Reliability:
1 (reliable without restriction)
Rationale for reliability incl. deficiencies:
guideline study
Qualifier:
according to
Guideline:
EU Method A.4 (Vapour Pressure)
Deviations:
no
GLP compliance:
yes (incl. certificate)
Remarks:
in compliance with UK GLP standards (Schedule 1, Good Laboratory Practice Regulations 1999 (SI 1999/3106 as amended by SI 2004/0994))
Type of method:
effusion method: vapour pressure balance
Key result
Temp.:
25 °C
Vapour pressure:
0.49 Pa

Table 1: Run 1

Temperature (ºC)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass Difference (kg)

Vapour Pressure (Pa)

Log10Vp

18

291.15

0.003434656

139.50

1.395E-07

0.193661740

-0.712956171

19

292.15

0.003422899

163.06

1.631E-07

0.226369056

-0.645182941

20

293.15

0.003411223

187.41

1.874E-07

0.260173094

-0.584737618

21

294.15

0.003399626

211.74

2.117E-07

0.293949367

-0.531727470

22

295.15

0.003388108

240.03

2.400E-07

0.333223135

-0.477264854

23

296.15

0.003376667

272.54

2.725E-07

0.378355344

-0.422100127

24

297.15

0.003365304

309.41

3.094E-07

0.429540350

-0.366996033

25

298.15

0.003354016

350.77

3.508E-07

0.486958627

-0.312507936

26

299.15

0.003342805

398.47

3.985E-07

0.553178447

-0.257134749

27

300.15

0.003331667

447.07

4.471E-07

0.620647699

-0.207154851

28

301.15

0.003320604

507.92

5.079E-07

0.705123088

-0.151735065

A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 1 gives the following statistical data using an unweighted least squares treatment.

Slope                                         -4854.996
Standard deviation in slope
           31.989

Intercept                                         15.971
Standard deviation in intercept
       0.108

The results obtained indicate the following vapour pressure relationship:

Log10(Vp (Pa)) = -4854.996/temp(K) + 15.971

The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -0.313.

Table 2: Run 2

Temperature (ºC)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass Difference (kg)

Vapour Pressure (Pa)

Log10Vp

18

291.15

0.003434656

145.55

1.456E-07

0.202060690

-0.694518169

19

292.15

0.003422899

165.38

1.654E-07

0.229589810

-0.639047391

20

293.15

0.003411223

190.47

1.905E-07

0.264421158

-0.577703797

21

294.15

0.003399626

215.77

2.158E-07

0.299544040

-0.523539317

22

295.15

0.003388108

243.71

2.437E-07

0.338331918

-0.470657029

23

296.15

0.003376667

274.78

2.748E-07

0.381465038

-0.418545260

24

297.15

0.003365304

311.19

3.112E-07

0.432011446

-0.364504746

25

298.15

0.003354016

351.62

3.516E-07

0.488138645

-0.311456809

26

299.15

0.003342805

397.40

3.974E-07

0.551693013

-0.258302516

27

300.15

0.003331667

448.13

4.481E-07

0.622119250

-0.206126360

28

301.15

0.003320604

507.25

5.073E-07

0.704192957

-0.152308323

A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 2 gives the following statistical data using an unweighted least squares treatment.

Slope                                         -4728.317
Standard deviation in slope
           17.188

Intercept                                         15.548
Standard deviation in intercept
       0.058

The results obtained indicate the following vapour pressure relationship:

Log10(Vp (Pa)) = -4728.317/temp(K) + 15.548

The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -0.311.

Table 3: Run 3

Temperature (ºC)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass Difference (kg)

Vapour Pressure (Pa)

Log10Vp

18

291.15

0.003434656

144.03

1.440E-07

0.199950540

-0.699077418

19

292.15

0.003422899

164.34

1.643E-07

0.228146024

-0.641787096

20

293.15

0.003411223

189.86

1.899E-07

0.263574322

-0.579096902

21

294.15

0.003399626

212.18

2.122E-07

0.294560200

-0.530825934

22

295.15

0.003388108

241.38

2.414E-07

0.335097281

-0.474829096

23

296.15

0.003376667

276.63

2.766E-07

0.384033312

-0.415631102

24

297.15

0.003365304

310.01

3.100E-07

0.430373304

-0.366154676

25

298.15

0.003354016

352.02

3.520E-07

0.488693947

-0.310963040

26

299.15

0.003342805

397.81

3.978E-07

0.552262198

-0.257854683

27

300.15

0.003331667

447.72

4.477E-07

0.621550065

-0.206523884

28

301.15

0.003320604

506.52

5.065E-07

0.703179530

-0.152933781

A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 3 gives the following statistical data using an unweighted least squares treatment.

Slope                                         -4770.362
Standard deviation in slope
           22.047

Intercept                                         15.688
Standard deviation in intercept
       0.074

The results obtained indicate the following vapour pressure relationship:

Log10(Vp (Pa)) = -4770.362/temp(K) + 15.688

The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -0.312.

 

Table 4: Run 4

Temperature (ºC)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass Difference (kg)

Vapour Pressure (Pa)

Log10Vp

18

291.15

0.003434656

146.46

1.465E-07

0.203324003

-0.691811349

19

292.15

0.003422899

164.35

1.644E-07

0.228159906

-0.641760670

20

293.15

0.003411223

188.79

1.888E-07

0.262088888

-0.581551392

21

294.15

0.003399626

215.77

2.158E-07

0.299544040

-0.523539317

22

295.15

0.003388108

241.78

2.418E-07

0.335652584

-0.474110005

23

296.15

0.003376667

273.83

2.738E-07

0.380146195

-0.420049352

24

297.15

0.003365304

309.76

3.098E-07

0.430026240

-0.366505043

25

298.15

0.003354016

349.39

3.494E-07

0.485042833

-0.314219908

26

299.15

0.003342805

395.21

3.952E-07

0.548652732

-0.260702454

27

300.15

0.003331667

444.95

4.450E-07

0.617704596

-0.209219168

28

301.15

0.003320604

505.70

5.057E-07

0.702041160

-0.153637425

A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 4 gives the following statistical data using an unweighted least squares treatment.

Slope                                         -4711.040
Standard deviation in slope
           19.150

Intercept                                         15.488
Standard deviation in intercept
       0.065

The results obtained indicate the following vapour pressure relationship:

Log10(Vp (Pa)) = -4711.040/temp(K) + 15.488

The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -0.313.

Conclusions:
The vapour pressure of the test material was determined to be 4.9 x 10^-1 Pa at 25 °C.
Executive summary:

The vapour pressure of the test material was determined by using a vapour pressure balance system. The study was GLP compliant and performed to EU Method A.4. The vapour pressure of the test material was determined to be 4.9 x 10 -1 Pa at 25 °C.

Description of key information

The vapour pressure of the test material was determined by using a vapour pressure balance system. The study was GLP compliant and performed to EU Method A.4. The vapour pressure of the test material was determined to tbe 4.9 x 10^-1 Pa at 25 °C.

Key value for chemical safety assessment

Vapour pressure:
0.49 Pa
at the temperature of:
25 °C

Additional information

Atwal SS et al (2010) was selected as the key study to fulfil the data requirement, as it was GLP compliant and performed to current internationally accepted guidelines. A reliability rating of 1 was assigned to this study, according to the criteria of Klimisch, 1997.

Supporting information is also available from a test material safety data sheet, Atofina Chemicals Inc. (2001).

A reliability rating of 4 was assigned to this study, according to the criteria of Klimisch, 1997 as this information is from a secondary source.

The vapour pressure for the test material is given as < 0.001 mm Hg at 20 °C.